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3 years ago

Given f(x)= a×e−bx , where a = 1 and b = 6,

Mathematics

1 answer:

krek1111 [17]3 years ago

8 0

Answer:

g(1) = -0.015

Step-by-step explanation:

We are given he following in the question:

$f(x) = ae^{-bx}$

For a = 1 and b = 6, we have,

$f(x) = e^{-6x}$

We have to find the the derivative of f(x) with respect to x.

$g(x) = \dfrac{d(f(x))}{dx} = \dfrac{d(e^{-6x})}{dx}\\\\g(x) = -6e^{-6x}\\\\g(1) = \dfrac{d(f(x))}{dx}\bigg|_{x=1} = -6e^{-6} = -0.015$

Thus, g(1) = -0.015

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Solve the inequality: -2x>-6

DedPeter [7]

Answer:

x < 3

Step-by-step explanation:

Divide both sides by -2

x < -6/-2

Two negatives equals a positive

x < 6/2

Simplify 6/2 to 3

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7 0

3 years ago

NO LINKS! Please help me with this problem.

Vedmedyk [2.9K]

$\\ \rm\Rrightarrow \dfrac{WX}{UV}=\dfrac{HI}{FE}$

$\\ \rm\Rrightarrow \dfrac{WX}{16}=\dfrac{10}{8}$

$\\ \rm\Rrightarrow WX/2=10$

$\\ \rm\Rrightarrow WX=20$

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$\\ \rm\Rrightarrow \dfrac{WX}{UT}=\dfrac{HI}{FG}$

$\\ \rm\Rrightarrow \dfrac{20}{20}=\dfrac{10}{FG}$

$\\ \rm\Rrightarrow FG=10$

7 0

2 years ago

Read 2 more answers

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Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

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3 years ago

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deff fn [24]

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3 years ago

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soldi70 [24.7K]

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