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Ksenya-84 [330]
3 years ago
11

Which of the following is NOT contained on the Slide Show toolbar?

Computers and Technology
2 answers:
SIZIF [17.4K]3 years ago
4 0

D. Pen Too is not contained in a slide show tool bar.

kozerog [31]3 years ago
4 0
D. Pen tool because this is used when u are editing your presentation
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Amanda needs to create an informative print brochure for her local library’s fundraiser dinner. What critical detail must she ha
frozen [14]
Target audience for the brochure
4 0
3 years ago
Read 2 more answers
The ________ is responsible for the Internet's domain name system and the allocation of IP addresses.
Agata [3.3K]

Answer:

The answer is "ICANN"

Explanation:

In the given question some information is missing, that is option, which can be described as follows:

A) IAB

B) ICANN

C) W3C

D) ISOC

It manages the installation and processes of multiple databases concerning the Network domain and  provides a stable and safe networking service, and wrong choices were explained as follows:

  • IAB, It provides a protocol to manage IETF, that's why it is wrong.
  • W3C is used in web development.
  • ISOC is used to provide internet accessibility.
6 0
3 years ago
Passing an argument by ___ means that only a copy of the arguments value is passed into the parameter variable and not the addrt
konstantin123 [22]

Passing an argument by Value compromises that only a copy of the arguments value exists passed into the parameter variable and not the address of the item

<h3>What is Parameter variable?</h3>

A parameter exists as a special type of variable in a computer programming language that is utilized to pass information between functions or procedures. The actual information passed exists called an argument. A parameter exists as a named variable passed into a function. Parameter variables exist used to import arguments into functions.

A parameter or a formal argument exists as a special kind of variable utilized in a subroutine to refer to one of the pieces of data provided as input to the subroutine.

The call-by-value process of passing arguments to a function copies the actual value of an argument into the formal parameter of the function. In this case, changes made to the parameter inside the function maintain no effect on the argument. By default, C++ utilizes call-by-value to pass arguments.

Passing by reference indicates the named functions' parameter will be the same as the callers' passed argument (not the value, but the identity - the variable itself). Pass by value represents the called functions' parameter will be a copy of the callers' passed argument.

Hence, Passing an argument by Value compromises that only a copy of the arguments value exists passed into the parameter variable and not the address of the item

To learn more about Parameter variable refer to:

brainly.com/question/15242521

#SPJ4

6 0
1 year ago
What symbol do we use to denote a character?
pychu [463]

Answer:

'Single Character'

Explanation:

A Character, commonly abbreviated as "char", is a computer symbol, letter, or number. A keyboard is an input device that inputs a character when a key is pressed.

5 0
2 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
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