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Black_prince [1.1K]
3 years ago
8

Does Windows 7 support secure boot in UEFI? Windows eight? Linux UBUNTU version 14?

Computers and Technology
1 answer:
Anni [7]3 years ago
4 0
Yes, windows 7 does support secure boot in UEFI. UEFI allows for backward compatibility. IT can boot a MBR hard drive and provides a BIOS boot through its Compatibility Support Module (CSM) feature.
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7.3 Code Practice edhesive
sladkih [1.3K]

Answer:

def print_sum(a,b,c):

 print(a+b+c)

one = int(input("Enter the 1st number: "))

two = int(input("Enter the 2nd number: "))

three = int(input("Enter the 3rd number: "))

print_sum(one,two,three)

Explanation:

hope this helped :)

5 0
2 years ago
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The _______ displays the name of the open file and the program.
Svetlanka [38]
The answer is a. Title Bar

The Title Bar displays the name of the program and the name of the current open file, whether it is just displayed or being edited. It is located at the top of the program window.
3 0
3 years ago
TRUE OR FALSE!!!!!
VladimirAG [237]
The answer is True.
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3 years ago
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. Generate 106 message bits (random binary values (bool/int) ). 2. Generate the corresponding code bits for r = 3, 5. This means
N76 [4]

Answer:

While loops are typically used when you don’t know how many times the loop needs to repeat. The body of the loop will repeat while the condition is true. The logical expression will be evaluated just before the body of the loop is repeated.

Let’s say that we want to find the square root of a number. For some square roots, you’re never going to be exact. Let’s say that we want to find a square root that, when multiplied by itself, is within 0.01 of the square we want. How do we do it? There’s a really old process that we can apply here.

Start by guessing 2.

Compute the guess squared.

Is the guess squared close to the target number? If it’s within 0.01, we’re done. We’ll take the absolute value of the difference, in case we overshoot. (In Python, abs is the absolute value function.)

If it’s not close enough, we divide the target number by our guess, then average that value with our guess.

That’s our new guess. Square it, and go back to Step #3.

Explanation:

7 0
3 years ago
c++ Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins wi
Margaret [11]

Answer:

The following are the program in the C++ Programming Language:

#include <iostream> //header file

#include <string>  //header file

#include <vector>  //header file

//name space

using namespace std;

//main function

int main() {

  vector<string> word; //set variable

  vector<int> c;  //set variable

  int s, counts = 0; //set variable

  string strng;  //set variable

  cout<<"Enter the size of string: "; //print message

  cin >> s; //get input

  cout<<"Enter the string: "; //print message

  for(int i = 0; i < s; ++i) {  //set for loop

     cin >> strng; //get input

     word.push_back(strng);

  }

  for(int i = 0; i < s; ++i) { //set for loop

         counts = 0;

         for(int j = 0;j<word.size();j++){ //set for loop

       if(word[j] == word[i]){ //set if statement

          counts++; //increament in counts

       }        

     }

      c.push_back(counts);

  }

  for(int i = 0; i < s; ++i) {

      cout << word[i] << " " << c[i] << endl;//print result

  }

  return 0;

}

<u>Output</u>:

Enter the size of string: 2

Enter the string: hello  sir

hello 1

sir 1

Explanation:

Here, we define three header files <iostream>, <String>, <vector> and namespace "std" after that we define main() method inside it.

  • Then, we set two vector type variables first one is string variable "word" and the second one is integer variable "c".
  • Then we set two integer variable "s" and "counts" and variable "counts" assign to 0.
  • Then, we get input from the user in variable "s" for the length of the loop.
  • Then, we set for the loop inside it, we get input in the variable "strng" from the user.
  • Then, we set the for loop for count the string repetition if any word comes again in the string then the value of count will increase.
  • Finally, we set for a loop to print the result.
4 0
3 years ago
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