Answer:
66
Step-by-step explanation:
If there are <em>n</em> students, then the number of pairs is 
.
With 12 students, 
pairs can be formed.
The reason the formula works is this: Each of the 12 students can be paired with 11 other students (no student is paired with him/her self). But counting 12 x 11 = 132 counts each pair <u>twice</u>. Example: student A can be paired with student B,..., student B can be paired with student A. The pair was counted two times.
See the attached image that shows pairings of 5 students. There are
5(5 - 1)/2 = 5(4)/2 = 10 pairs.
6/10
0.6
60 cents
17/100
0.17
17 cents
49/100
0.49
49 cents
92/100
0.92
92 cents
Answer:
The answer is 7/36.
Step-by-step explanation:
First, you find out how many possible outcomes there are from rolling a pair of dice. On one cube, you can roll a 1,2,3,4,5, or 6; so there are 6 outcomes. Since there are two cubes, you multiply 6 by itself to get a total of 36 possible outcomes. Next, you find the probability of the sum of the numbers rolled being an even number; the possibilities are 2,4,6,8,10, or 12, which is 6/36. The probability of rolling a multiple of 5; the one possibility is just 5, since we already accounted for rolling a 10 as an even number. So that is 1/36. The word <u>or</u> says that we add the two probabilities, so the final answer is 6/36+1/36=7/36.
Answer:
y ≤ –2x + 3
Step-by-step explanation: i got it right on edge 2020
Answer:
the transistors have L=1 mm of linear size
Step-by-step explanation:
For the silicon chip the area is A=1 cm² and for the transistors the area is At=L² (L=linear size) . Then since N= 10 billion transistors of area At should fit in the area A
A=N*At
A=N*L²
solving for L
L= √(A/N)
Assuming that 1 billion=10⁹ (short scale version of billion), then
L= √(A/N) = √(1 cm²/10⁹) = 1 cm / 10³ = 1 mm
then the transistors have L=1 mm of linear size
