The values of x are -22 and -2 and there are not extraneous solutions
<h3>How to solve the equation?</h3>
The equation is given as:
2|x + 7|= x - 8
Expand the absolute bracket
|2x + 14|= x - 8
Remove the absolute bracket
2x + 14 = x - 8 and 2x + 14 = -x + 8
Evaluate the like terms
x = -22 and 3x = -6
This gives
x = -22 and x = -2
Hence, the values of x are -22 and -2 and there are not extraneous solutions
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Answer:
the magnitude is 7
Step-by-step explanation:
as i means unit vector along x-axis so the magnitude of i is 1 and now,
= 12 - 5×1
= 12- 5
= 7
Answer:
Step-by-step explanation:
Step-by-step explanation:
a = 2i + j - k
b = -1 -7j + k
a × b = (2i + j - k) (-1 + 7j + k)
-2i + 14ij + 2ik - j + 7j^2 + jk + k -7jk - k^2
-2i + 14ij + 2ik -j +7j^2 +jk - 7jk + k - k^2
-2i + 14ij + 2ik - j +7j^2 - 6jk + k - k^2
A: 7x+y=8 is the right answer, because if we move 7x to the other side we get: y=-7x+8
