fg^3 / g^3f = 1
f^4 / f*f*f*f = f^4 / f^4 = 1
f^2g^3 / f^3g^2 = g/f
f*f/f^2 = f^2 / f^2 = 1
Answer:
f^2g^3 / f^3g^2
Answer:
Group b most likely has a lower mean age of salsa students
Step-by-step explanation:
Arithmetic Mean of the data is the average of a set of numerical values, calculated by adding them together and dividing by the number of terms in the set.
Here we are given with two groups that are Group A and Group B
both having total number of students = 20
Here the mean age of the data is addition of the all ages of different students divided by total number of students.
For group a
total age of the group = 3 × 5 + 4 × 10 + 6 × 17 + 4 × 24 + 3 × 29
= 15 + 40 + 102 + 96 + 87
=340
The mean age of salsa students= 340 ÷ 20 = 17
For group b
total age of the group = 6 × 7 + 3 × 10 + 4 × 14 + 5 × 16 + 2 × 21
= 42 + 30 + 56 + 80 + 42
=250
The mean age of salsa students= 250 ÷ 20 = 12.5
So the group b most likely has a lower mean age of salsa students
Learn more about Arithmetic Mean here - brainly.com/question/24688366
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Answer:
24+16= 40
24-16=8 if it's wrong, try and make ur question more specific, thanks
Step 1. Use Multiplication Distributive Property
4*3^3(x^2)^3(y^4)^3
Step 2. Simplify 3^3 to 27
4*27(x^2)^3(y^4)^3
Step 3. Use the Power Rule
4*27x^6(y^4)^3
Step 4. Use the Power Rule
4*27x^6y^12
Step 5. Simplify.
The answer is 108x^6y^12
