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stepladder [879]
3 years ago
10

FIND X!!!!!!!!!!!!?!!!?!!,!?

Mathematics
2 answers:
jasenka [17]3 years ago
7 0
The hypotenuse is twice the short leg. The answer is 8
anastassius [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Sin(30) = 4/x

Multiply x by both sides

Sin(30) (x) = 4

Then divide sin(30)

X= 4/sin(30)

Put 4/sin(30) into calculator to get 8

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damaskus [11]
4 hundreds x 10= 4000
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3 years ago
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Which of the following is a Geometric Series?
Katarina [22]

I dont know the answer

Step-by-step explanation:

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Sphere A is similar to Sphere B. The scale factor of the lengths of the radii of Sphere A to Sphere B is 1 to 4. Sphere A has th
AleksAgata [21]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432

3 0
3 years ago
Line segment JK measures 17cm. Segments JK was translated 4 units right and 8 units up for for J'K'. What is the measurement of
castortr0y [4]

Answer:

c

Step-by-step explanation:

8 0
2 years ago
Determine the center and radius of the following circle equation:
UkoKoshka [18]

Answer:

The equation of the circle  <em>(x + 5 )² + ( y + 10 )² = (4)²</em>

<em>Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle     ' r' = 4</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given circle equation is x² + y² +10 x + 20 y +109 =0

                                     x² +10 x +  y² + 20 y +109 =0

  x² +2 (5) (x)+(5)² -(5)²+ y² +2(10) y + (10)²-(10)² +109 =0

<em>By using formula </em>

<em>(a+b)² = a² + 2 a b + b²</em>

<em>(x + 5 )² + ( y + 10 )² - 25 - 100 + 109 = 0</em>

<em>(x + 5 )² + ( y + 10 )² - 16 = 0</em>

<em>(x + 5 )² + ( y + 10 )² = 16</em>

(x + 5 )² + ( y + 10 )² = (4)²

The standard equation of the circle  ( x - h )² + ( y -k)² = r²

<em> Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle     ' r' = 4</em>

<u><em>Conclusion</em></u><em>:-</em>

The equation of the circle  <em>(x + 5 )² + ( y + 10 )² = (4)²</em>

<em>Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle     ' r' = 4</em>

<em></em>

3 0
2 years ago
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