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Leya [2.2K]
3 years ago
8

Gerald is constructing a line parallel to line l through point P. He begins by drawing line m through points P and Q. He then dr

aws a circle centered at Q, which intersects line l at point N and line m at point S. Keeping the compass measure, he draws a congruent circle centered at point P, which intersects line m at point T. Which next step will create point R, such that when a line is drawn through points P and R, the line will be parallel to line l? Lines m and n intersect at point Q. A circle is drawn around point Q and forms point S on line m and forms point N on line l. Point P is also on line m. A circle is drawn around point P and forms point T on line m. Use the compass to construct a circle centered at Q through point P. Using the compass measure between points S and N, draw an arc to the right of line m, centered at T, intersecting the edge of circle P. Using the compass measure between points S and N, draw an arc above line l, centered at N, intersecting the edge of circle Q. Use the compass to construct a circle centered at P through point Q.
Mathematics
1 answer:
True [87]3 years ago
4 0

Answer:

The answer is B on Edge

Step-by-step explanation:

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In a relay race, Nancy ran her part in 15.25 seconds, John ran his part in 13.8 seconds, Sylas ran his part in 16.4 seconds. Wha
sp2606 [1]

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45.45

Step-by-step explanation:

7 0
3 years ago
Which of the following statements are true?
bezimeni [28]

Answer:

A, B, and C are all true.

Step-by-step explanation:

A. 6 is neither a perfect square nor a perfect cube.   True

B. 16 is a perfect square.   True 4^{2}

C. 27 is a perfect cube.   True 3^{3}

OD. 1,331 is both a perfect square and a perfect cube.   False

E. 9 is a perfect cube.  False

6 0
3 years ago
A meal costs $30 before tax and tip.
Korolek [52]

Answer:

33.48

Step-by-step explanation:

30*0.07=2.10

30-2.10=27.90

27.90*0.20=5.58

27.90+5.58

33.48

5 0
3 years ago
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
4 years ago
Can someone help please?!! Major Help Pic above
Mila [183]
I believe it’s c. I hope that this is helpful!
8 0
4 years ago
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