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3 years ago

Which scales are equivalent to the scale 1cm to 5km? More than one is the right answer

Mathematics

2 answers:

Oduvanchick [21]3 years ago

8 0

The answer would be A because each side is being multiplied by 3

bearhunter [10]3 years ago

6 0

Answer:

Option A and D.

Step-by-step explanation:

The scale is given 1 centimeter = 5 kilometers

We have to find the equivalent scales from the given options.

A. 3 cm to 15 km

∵ 1 cm to 5 km

∴ 3 cm to 3 × 5 = 15 km

This option is right.

B. 1 mm to 150 km

∵ 1 mm = 0.1 cm

∴ 0.1 cm = 150 km

This is not the correct option

C 5 Cm to 1 km

∵ 1 cm to 5 km

∴ 5 cm = 5 × 5 = 25 km

This option is incorrect.

D. 5 mm to 2.5 km

1 cm = 10 mm

5 mm = 0.5 cm

∵ 0.5 cm = 2.5 km

∴ 1 cm = 2.5 ÷ 0.5 = 5 km

This is the correct option

E. 1 mm to 500 km

10 mm = 1 cm

1 cm to 5000 km

This is not correct

Therefore, Option A and D is equivalent to the scale.

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Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

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Vinil7 [7]

Distance = 13 units

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Point B: (-4, -2)

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$\sqrt{169}$

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Step-by-step explanation:

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