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4 years ago

11

The students lockers at a college are to be numbered consecutively form 1 to 800 using plastic digits. Each digit cost 10c. What

will be the total cost of all the digits?

1 answer:

KIM [24]4 years ago

6 0

Answer would be eight because you divide eight hundred by ten cents to get eight.

You might be interested in

Please help to find an explicit formula for calculating the sum Mn

defon

The explicit formula for calculating the sum is

$S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}$

The sum of the nth term of a sequence is expressed as;

$S_n=\frac{n}{2}(2a+(n-1)d)$

a is the first term

d is the common difference

n is the number of terms

For the sequence 0 + 1 + 2 + 3 +...

$S_n=\frac{n}{2}(2(0)+(n-1)1)\\S_n= \frac{n}{2}(n-1)\\S_n= \frac{n(n-1)}{2}$

Similarly for the sequence:

1 + 2+ 3 + 4+...

$S_n=\frac{n}{2}(2(1)+(n-1)1)\\S_n= \frac{n}{2}(2+n-1)\\S_n= \frac{n(n+1)}{2}$

Taking the product of the sum to get the explicit formula for calculating the sum

$S_N=\frac{n(n-1)}{2} \cdot\frac{n(n+1)}{2}$

Learn more here: brainly.com/question/24547297

8 0

2 years ago

Find the length of side b<br><br> I need help plss

MrMuchimi

20

.......…......?7)$:&:&:7$:$;$;)$3$3$;$

6 0

3 years ago

A class has 6 boys and 15 girls what is the ratio of boys to girls

inessss [21]

Hey there!

Ratio = division

now, division of boys over girls

= 6 / 15

= 2 / 5

Ratio = 2 : 5

Hope helps!

6 0

3 years ago

If f(x)=2[x] , find f( -1/4) <br>(A) -2 <br>(B) - 1/2 <br>(C) 0<br>(D) 1/2

Keith_Richards [23]

Answer:

b)-1/2 is the required answer

Step-by-step explanation:

$f(x) = 2x (given)$

$when \: x = - \frac{1}{4}$

4 0

3 years ago

Read 2 more answers

Find the roots of:

Elena-2011 [213]

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \ 2x^3-7x^2+8x-3=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

| 2 -7 8 -3

<u>1 | 2 -5 3</u>

| 2 -5 3 0

<u> 1 | 2 -3 </u>

2 -3 0

So the factorization is (x-1)² (2x-3)=0. So:

$\bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2} }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \ x^3-x^2-4=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

| 1 -1 0 -4

<u>2 | 2 2 </u>

1 2 2 0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

$\bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \ 6x^3+7x^2-9x+2=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

| 6 7 9 2

<u>-2 | -12 10 -2</u>

6 -5 1 0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

$\bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}$

$\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}$

6 0

2 years ago