4 years ago

What is the expanded form of 3x(x+3)^2?

Mathematics

1 answer:

Ulleksa [173]4 years ago

7 0

Pemdas
exponents first
(x+3)^2=(x+3)(x+3)=x^2+3x+3x+9=x^2+6x+9
multiply
3x(x^2+6x+9)
3x^3+18x^2+27x

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