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Murljashka [212]
4 years ago
11

What is the expanded form of 3x(x+3)^2?

Mathematics
1 answer:
Ulleksa [173]4 years ago
7 0
Pemdas
exponents first
(x+3)^2=(x+3)(x+3)=x^2+3x+3x+9=x^2+6x+9
multiply
3x(x^2+6x+9)
3x^3+18x^2+27x
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Combine like terms to create an equivalent expression.
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Answer is in the file below

tinyurl.com/wpazsebu

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3. A person standing 3 feet away from the base of a lamp post casts a shadow 4 feet long. If the person is 6 feet tall and walks
german

Answer:

533.33 ft/min

Step-by-step explanation:

We are given that

x=3 feet

y=4 feet

Height of person,h=6 feet

\frac{dx}{dt}=400 ft/min

Triangle ABC and A'B'C are similar because all right triangles are similar

By using similarity property

\frac{h'}{6}=\frac{7}{4}

h'=10.5 feet

x+y=3+4=7 feet

\frac{h'}{6}=\frac{x+y}{y}

\frac{10.5}{6}=\frac{x+y}{y}

10.5y=6x+6y

10.5y-6y=6x

4.5y=6x

Differentiate w.r.t t

4.5\frac{dy}{dt}=6\frac{dx}{dt}

\frac{dy}{dt}=\frac{6\times 400}{4.5}ft/min

\frac{dy}{dt}=533.33ft/min

Hence, If the person is 6 feet tall and walks away from the lamp post at a speed of 400 feet per minute then his shadow moving at the rate 533.33 ft/min

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3 years ago
Find the value of x for which the lines l and m are parallel.
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Answer:

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l // m

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