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ICE Princess25 [194]
3 years ago
9

Drag numbers to complete the table for missing values of x, x2, and x3.

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer: The filled out table is shown in the attachment below

Row 1 = 2, 4, 8

Row 2 = 6, 36, 216

=======================================================

Explanation:

In the first row we have x^2 = 4. Apply the square root to both sides to get x = 2. It appears your teacher is making x positive.

So we'll have 2 in the first box of row 1.

If x = 2, then x^3 = 8 after cubing both sides.

In other words, x^3 = 2^3 = 2*2*2 = 8

The value 8 goes in the other box of row 1.

---------------

For row 2, we use x = 6 to square that to get x^2 = 6^2 = 6*6 = 36.

36 will go in the blank box for row 2

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Two times antonio's age plus three times Sarah's age equals 34. Sarah age is also five times antonio's age . How old is Sarah?
Sergio039 [100]
Let Sarah's age be s and Antonio's age be a.

According to your question,

2a + 3s = 34
s = 5a

substituting the value of s in eq. 1,

2a + 3(5a) = 34

= 2a + 15 a = 34

17a = 34

thus, a = 34/17 = 2

substituting the value of a is s,

s = 5(2)
= 10

Thus, Sarah's age is 10 years and Antonio's age is 2 years.
6 0
3 years ago
Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.
zloy xaker [14]

Answer:

y=\frac{-3\pm\sqrt{4sin2x+1}}{2}

x={\pi}{4}

Step-by-step explanation:

We are given that

y'=\frac{2cos2x}{3+2y}

y(0)=-1

\frac{dy}{dx}=\frac{2cos2x}{3+2y}

(3+2y)dy=2cos2x dx

Taking integration on both sides then we get

\int (3+2y)dy=2\int cos 2xdx

3y+y^2=sin2x+C

Using formula

\int x^n=\frac{x^{n+1}}{n+1}+C

\int cosx dx=sinx

Substitute x=0 and y=-1

-3+1=sin0+C

-2=C

sin0=0

Substitute the value of C

y^2+3y=sin2x-2

y^2+3y-sin 2x+2=0

y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}

By using quadratic formula

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

y=\frac{-3\pm\sqrt{9+4sin2x-8}}{2}=\frac{-3\pm\sqrt{4sin2x+1}}{2}

Hence, the solution y=\frac{-3\pm\sqrt{4sin2x+1}}{2}

When the solution is maximum then y'=0

\frac{2cos2x}{3+2y}=0

2cos2x=0

cos2x=0

cos2x=cos\frac{\pi}{2}

cos\frac{\pi}{2}=0

2x=\frac{\pi}{2}

x=\frac{\pi}{4}

3 0
3 years ago
If the farmer has 152 feet of fencing, what are the dimensions of the region with the largest area?
GuDViN [60]

What's the shape of what the farmer is fencing?

8 0
3 years ago
Read 2 more answers
Checkpoint Quiz 1<br> 1. Write a formula for finding the area of a parallelogram.<br> le
azamat

Answer:

The formula for area of a parallelogram is either A=bh or A=\dfrac{d_1d_2}{2}.

Step-by-step explanation:

If base and vertical height of a parallelogram are given, then the area of the parallelogram is:

A=bh

Where, <em>b</em> is base and <em>h</em> is the vertical height of the parallelogram.

If measures of both diagonals are given, then the area of the parallelogram is:

A=\dfrac{d_1d_2}{2}

Where, d_1,d_2 are the two diagonals of the parallelogram.

5 0
3 years ago
Dividing, -please please please help?
harkovskaia [24]
B should be the answer Hope this helps.
5 0
4 years ago
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