Drag numbers to complete the table for missing values of x, x2, and x3.
1 answer:
Answer: The filled out table is shown in the attachment below
Row 1 = 2, 4, 8
Row 2 = 6, 36, 216
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Explanation:
In the first row we have x^2 = 4. Apply the square root to both sides to get x = 2. It appears your teacher is making x positive.
So we'll have 2 in the first box of row 1.
If x = 2, then x^3 = 8 after cubing both sides.
In other words, x^3 = 2^3 = 2*2*2 = 8
The value 8 goes in the other box of row 1.
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For row 2, we use x = 6 to square that to get x^2 = 6^2 = 6*6 = 36.
36 will go in the blank box for row 2
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Answer:
see below
Step-by-step explanation:
y = 8x − 9
y = 4x − 1
Since both equations are equal to y, we can set them equal to each other
8x-9 = 4x-1
Subtract 4x from each side
8x-4x-9 = 4x-4x-1
4x-9 = -1
Add 9 to each side
4x-9+9 = -1+9
4x = 8
Divide each side by 4
4x/4 = 8/4
x=2
Now find y
y = 4x-1
y = 4(2)-1
y = 8-1
y = 7
(2,7)
The point of intersection when the 2 lines are graphed is (2,7)
