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crimeas [40]
3 years ago
7

What account should never be used in a service business?

Mathematics
2 answers:
Murljashka [212]3 years ago
8 0

What are the choices to pick from?

miss Akunina [59]3 years ago
8 0

what are the choices

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Show the following numbers on number line 3/2, 5/2, -3/2
pav-90 [236]

When you create the number line, put 0 in the middle. Basically you put all the numbers you got from least to greatest on the number.

Since -3/2 is less than 0, it will go to the left of 0.

Since 3/2 and 5/2 are greater than 0, it will go to the right of 0.

Remember to use sub points of 1.

Best of Luck!

3 0
3 years ago
1. For the function f(x) = 3x + 1, find f(-2). (substitute -2 in for x)
puteri [66]

Answer:

f(-2) = -5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x + 1

f(-2) is x = -2

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    f(-2) = 3(-2) + 1
  2. Multiply:                               f(-2) = -6 + 1
  3. Add:                                     f(-2) = -5
4 0
3 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
What is the fifth term in the sequence defined by f(n)=3(n-3)
Sholpan [36]
The answer is n= 3.

Hope this helps.
8 0
3 years ago
Read 2 more answers
Find the equation of the graphed line.
yulyashka [42]
It’s the first one; a)
3 0
3 years ago
Read 2 more answers
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