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baherus [9]
3 years ago
14

Please solve 21 points plsss help :()

Mathematics
1 answer:
asambeis [7]3 years ago
7 0

Answer:

Answer = 61/157

Step-by-step explanation:

First add all the numbers together.

56 + 61 + 14 + 26 = 157

Then take the number of brown hair and blue eyed people (61) and make a fraction out of all.

61/157

You can not simplify it more than that

Hope this helps

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Consider the equation below <br> -2(bx -5 ) =16
gladu [14]

Answer:

bx = - 3

Step-by-step explanation:

- 2(bx - 5) = 16

- 2bx + 10 = 16

- 2bx + 10 - 10 = 16 - 10

- 2bx = 6

- 2bx ÷ - 2 = 6 ÷ - 2

bx = - 3

8 0
2 years ago
$6,000 is invested in two different accounts earning 3% and 5% interest at the end of one year to two accounts earn $220 in inte
Svetradugi [14.3K]
My answer: $2000 were invested at 5%

Let x amount of money was invested at 5% and (6000-x) amount was invested as 3%
6 0
2 years ago
Help plz ill give some brainlynest plz just help
kirill [66]

Answer:

.95

Step-by-step explanation:

Using pythagorean theroem to calculate the missing side it's 35

35/37 = .94594597

or sin of angle a 71.07536 = .94594597

8 0
2 years ago
It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha
stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.54% of the calls receive a busy signal, hence  p = 0.0054.
  • A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

P(X \geq 5) = 1 - P(X < 5)

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009

P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062

P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218

P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513

P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0
1 year ago
Simplified form the eaquation
IRINA_888 [86]

Answer: C

Step-by-step explanation: You want to find the square root of each number given. The square root of 400 is 20, and the square root of 100 is 10

3 0
3 years ago
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