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aev [14]
3 years ago
11

Factor the trinomial x^2-13x+40

Mathematics
1 answer:
suter [353]3 years ago
6 0
X^2-13x+40
X^2-8x-5x+40
X(x-8)-5(x-8)


(X-5)(x-8)

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Please help I’ll mark you as brainliest if correct
nadezda [96]

Answer:

I  think it is c

Step-by-step explanation:

because if you try to solve it you get that answer

5 0
2 years ago
If 3x + 5y = 2 and 2x - 4y = 20, what is 5x - y?
gavmur [86]

Answer:

= 298/11

Step-by-step explanation:

3x + 5y = 2 | ×2 |

2x - 4y = 20 | ×3 |

6x + 10y = 4

6x - 12y = 60

____________--

22y = -56

y = -56/22

y = -28/11

3x + 5y = 2 | ×4 |

2x - 4y = 20 | ×5 |

12x + 20y = 8

10x - 20y = 100

_____________+

22x = 108

x = 108/22

x = 54/11

5x - y

= 5(54/11) - (-28/11)

= 270/11 + 28/11

= 298/11

8 0
3 years ago
90/110 reduce the fraction
IrinaVladis [17]
90/110 reduces to 9/11. Good luck!
6 0
3 years ago
Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x
valkas [14]
\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k
\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)


Let \mathcal D be the region whose boundary is \mathcal S. Then by the divergence theorem,

\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV

Convert to cylindrical coordinates, setting

x=r\cos\theta
y=r\sin\theta

and keeping z as is. Then the volume element becomes


\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz

and the integral is

\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\dfrac{2\pi}3
4 0
3 years ago
1. Which equation is the inverse of y = 2x2 + 25 ?​
Alborosie
Imma go with F just because I think it’s right
3 0
3 years ago
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