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Zigmanuir [339]

3 years ago

6

During the summer, Vontavious makes $8.50 working for his

1 answer:

bekas [8.4K]3 years ago

6 0

Answer:

60 hours

Step-by-step explanation:

I multiplied 8.50 by 60 and got 510

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Are 1/2 equivalent to 4/8

Lerok [7]

Yes, 1/2 is equivalent to 4/8, because 4/8 reduced to simplest form is 1/2.

6 0

3 years ago

Read 2 more answers

If y varies inversely with 2.5x, and y=5.6 and x=30, write an equation to represent this relationship

klasskru [66]

Let the constant of variation be c.
We are given that y varies inversely with 2.5x, this means that:
y = (c) / (2.5x)
This can be written as:
2.5xy = c

Now, we a re given that y = 5.6 at x = 30.
Substitute with these values in the equation to get the value of c as follows:
2.5xy = c
2.5(30)(5.6) = c
c = 420

Therefore, the equation that describes the relation is:
2.5xy = 420

3 0

3 years ago

Phillip claimed that the expression − p + 5 + p is positive for any value of p. Determine whether Phillip’s statement is always

DIA [1.3K]

Answer:

always true.

the expression will always be equal to +5 because -p+p is zero

at any given value to p, the value is constantly +5

8 0

3 years ago

Read 2 more answers

solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

$P(t)=A(r)^t$

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

$\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}$

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}$

Solve for A. Simplify:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^3$

Simplify:

$\displaystyle 2=A\Big(\frac{1}{8}\Big)$

Thus, the initial mass of the sample was:

$A=16\text{ mg}$

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

$\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}$

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

5 0

3 years ago

Find the mean, median, and mode for 0, 4, 6, 11, 9, 8, 9, 1, 5, 9, 7. Round to the nearest tenth if needed.

snow_lady [41]

Answer:

6

Step-by-step explanation:

you add them all up and divide it by how many numbers there are

6 0

3 years ago