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3 years ago

What is 35% of 1070.35(10) =

Mathematics

1 answer:

NISA [10]3 years ago

3 0

Answer:

37.45percent

our output is 100

we represent unknown value with x

first step Above , 100 equals 100%

similarity x equals 35 percent

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point O lies between points M and P on a line. OM = 34z and OP = 36z -7. if point N is the midpoint of MP, what algebraic can yo

zalisa [80]

N=1/2MP? Since n would be the midpoint you have to divide the segment into two.

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3 years ago

Suppose the heights of 18-year-old men are approximately normally distributed, with mean 65 inches and standard deviation 4 inch

Serhud [2]

Answer:

Step-by-step explanation:

a)

Given that ; X ~ N ( µ = 65 , σ = 4 )

P ( 64 < X < 66 )

From application of normal distribution ;

Z = ( X - µ ) / σ, Z = ( 64 - 65 ) / 4, Z = -0.25

Z = ( 66 - 65 ) / 4, Z = 0.25

Hence, P ( -0.25 < Z < 0.25 ) = P ( 64 < X < 66 ) = P ( Z < 0.25 ) - P ( Z < -0.25 ) P ( 64 < X < 66 ) = 0.5987 - 0.4013

P ( 64 < X < 66 ) = 0.1974

b) X ~ N ( µ = 65 , σ = 4 )

P ( 64 < X < 66 )

From normal distribution application ;

Z = ( X - µ ) / ( σ / √(n)), plugging in the values,

Z = ( 64 - 65 ) / ( 4 / √(12)) = Z = -0.866

Z = ( 66 - 65 ) / ( 4 / √(12)) = Z = 0.866

P ( -0.87 < Z < 0.87 )

P ( 64 < X < 66 ) = P ( Z < 0.87 ) - P ( Z < -0.87 )

P ( 64 < X < 66 ) = 0.8068 - 0.1932

P ( 64 < X < 66 ) = 0.6135

c) From the values gotten for (a) and (b), it is indicative that the probability in part (b) is much higher because the standard deviation is smaller for the x distribution.

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3 years ago

How dose a scale factor greater than 1 affect a scale copy?Explain.

olchik [2.2K]

When a shape gets dilated by a scale factor larger than 1, the area, perimeter, and lengths will be increased. However, angles will stay the same.

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3 years ago

What is the slope of this graph 4 -1/4 1/4 -4

vodka [1.7K]

Answer:

-4

Step-by-step explanation:

From (-1,1) to (0,-3) is a fall of 4 and a run of 1

therefore rise over run = -4/1 = -4

Slope Formula

$slope = m = \frac{rise}{run}=\frac{change~in~y}{change~in~x} = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} =$ -4

Hope this helps,

8 0

2 years ago

Can you guys pls help me with this math question

Sindrei [870]

Answer:

Dimensions: 150 m x 150 m

Area: 22,500m²

Step-by-step explanation:

Given information:

Rectangular field
Total amount of fencing = 600m
All 4 sides of the field need to be fenced

Let $x$ = width of the field

Let $y$ = length of the field

Create two equations from the given information:

Area of field: $A= xy$

Perimeter of fence: $2(x + y) = 600$

Rearrange the equation for the perimeter of the fence to make y the subject:

$\begin{aligned} \implies 2(x + y) & = 600\\ x+y & = 300\\y & = 300-x\end{aligned}$

Substitute this into the equation for Area:

$\begin{aligned}\implies A & = xy\\& = x(300-x)\\& = 300x-x^2 \end{aligned}$

To find the value of x that will make the area a maximum, differentiate A with respect to x:

$\begin{aligned}A & =300x-x^2\\\implies \dfrac{dA}{dx}& =300-2x\end{aligned}$

Set it to zero and solve for x:

$\begin{aligned}\dfrac{dA}{dx} & =0\\ \implies 300-2x & =0 \\ x & = 150 \end{aligned}$

Substitute the found value of x into the original equation for the perimeter and solve for y:

$\begin{aligned}2(x + y) & = 600\\\implies 2(150)+2y & = 600\\2y & = 300\\y & = 150\end{aligned}$

Therefore, the dimensions that will give Tanya the maximum area are:

150 m x 150 m

The maximum area is:

$\begin{aligned}\implies \sf Area_{max} & = xy\\& = 150 \cdot 150\\& = 22500\: \sf m^2 \end{aligned}$

5 0

1 year ago

What is 35% of 1070.35(10) =​

What is 35% of 1070.35(10) =