Answer:
4.19
Step-by-step explanation:
If rounded to the nearest dime 4.20
nice
Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that 
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.




The minimum score required for an A grade is 83.
Your first answer is correct but I’m not sure if your second is. But I’m leaning towards it is not correct.
Hope this helps!
(Don’t forget to mark branliest if it is correct :) )
Answer:19/20
1-20=19
1÷20=0.05
0.05=5%
I hope this is good enough:
Answer:
i. The horizontal component of the ball = 15.8
ii. The vertical component of the ball = 11.2
Step-by-step explanation:
A thrown ball is an example of a projectile, whose motion can be explained with respect to both horizontal and vertical components.
Horizontal component of the ball = U Cos θ
Vertical component of the ball = U Sin θ
where U is the initial velocity of the ball, and θ is the angle of projection.
Thus for the given question,
U = 70 km/hr (19.44 m/s)
θ = 35°
So that;
i. The horizontal component of the ball = 19.44 Cos 35°
= 19.44 x 0.8192
= 15.785
The horizontal component of the ball = 15.8.
ii. The vertical component of the ball = 19.44 Sin 35°
= 19.44 x 0.5736
= 11.151
The vertical component of the ball = 11.2