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4 years ago

The sale price of a trampoline before tax is $300 the sales tax is 4% find the sales tax in the total price of the trampoline

Mathematics

2 answers:

Gemiola [76]4 years ago

3 0

Answer:

its 12

Step-by-step explanation:

you 0.04 times 300 then subtract 12-300

valentinak56 [21]4 years ago

3 0

Answer:

but whats the total price

Step-by-step explanation:

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What is the value of the expression 8.3 × 104 − 2.5 × 103 − 1.9 × 104 written in scientific notation?

bezimeni [28]

Remark work with the two numbers that are 10^4 first. Then add in the one that goes to 10^3

Method one
You could change these all to integers and then take it back to scientific notation.

83 000
-19 000
64 000
- 2 500
 61 500 <<<<<< answer

Method two
Keep the scientific notation.
8.3 * 10^4
-1.9 * 10^4
6.4 * 10^4
- .25*10^4 Note the powers of ten must be the same.
6.15*10^4 <<<<<<<< answer

Either method works.

You could use your calculator to get the right answer. I'm not sure all calculators retain the scientific notation. Test yours to see what it does. Enter 8.3*10y^x 4 *1 =

Your calculator might have x^y or ^ to record powers. You may also have EE and one of your keys.

See if your calculator returns 8.3*10^4 or if it returns 83000

4 0

3 years ago

Read 2 more answers

PLS HELP QUICK! LINKS WILL BE REPORTED....

Semenov [28]

I think it’s dababy I’m not sure

8 0

3 years ago

Arandom sample of n1 =12 students majoring in accounting in a college of business has a mean grade-point average of 2.70 (where

antiseptic1488 [7]

Answer:

We accept the null hypothesis that the mean gpa's are equal, with the 5 percent level of significance.

Step-by-step explanation:

We have these following hypothesis:

Null

Equal means

$\mu_{1} = \mu_{2}$

Alternative

Different means

$\mu_{1} \neq \mu_{2}$

Our test statistic is:

$\frac{\overline{Y_{1}} - \overline{Y_{2}}}{\sqrt{\frac{s_{1}^{2}}{N_{1}} + \frac{s_{2}^{2}}{N_{2}}}}$

In which $\overline{Y_{1}}, \overline{Y_{2}}$ are the sample means, $N_{1}, N_{2}$ are the sample sizes and $s_{1}, s_{2}$ are the standard deviations of the sample.

In this problem, we have that:

$\overline{Y_{1}} = 2.7, s_{1} = 0.4, N_{1} = 12, \overline{Y_{2}} = 2.9, s_{2} = 0.3, N_{2} = 10$

$T = \frac{2.7 - 2.9}{\sqrt{\frac{0.4}^{2}{12} + \frac{0.3}^{2}{10}}} = -1.3383$

What to do with the null hypothesis?

We will reject the null hypothesis, that is, that the means are equal, with a significante level of $\alpha$ if

$|T| > t_{1-\frac{\alpha}{2},v}$

In which v is the number of degrees of freedom, given by

$v = \frac{(\frac{s_{1}^{2}}{N_{1}} + \frac{s_{2}^{2}}{N_{2}})^{2}}{\frac{\frac{s_{1}^{2}}{N_{1}}}{N_{1}-1} + \frac{\frac{s_{2}^{2}}{N_{2}}}{N_{2} - 1}}$