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2 years ago

Can someone pls help me solved this problem! I need help ASAP!

Mathematics

1 answer:

kaheart [24]2 years ago

5 0

Answer:

Step-by-step explanation:

2N - 3 = 5

2N = 5 +3 = 8

N = 8/2 = 4

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Trey has plastic cubes stored in a box that measures 4 ft long, 2 1/2 ft wide, and 2 ft tall. The edge length of each plastic cu

iVinArrow [24]

Your answer is 160 i had this on a test hope this helps

4 0

2 years ago

Read 2 more answers

The coordinates of the vertices if JKL are J(0,2),K(3,1),And K(1,-5)

Anika [276]

Answer:

K(3,1),And K(1,-5),j(0,2) t

Step-by-step explanation:

7 0

2 years ago

Geometry question!!

Mademuasel [1]

Answer:

GQ=25 units

Step-by-step explanation:

we know that

Point Q is the midpoint of GH

GH=GQ+QH and GQ=QH

GH=2GQ -------> equation A

we have

GH=5x-5

GQ=2x+3

substitute in the equation A and solve for x

5x-5=2(2x+3)

5x-5=4x+6

5x-4x=6+5

x=11

Find the length of GQ

GQ=2x+3

substitute the value of x

GQ=2(11)+3

GQ=25 units

4 0

3 years ago

Zane way to color meatballs during a science class the blue ball weighs 7 lb in the green ball weighed 0.69 lb in the same place

Umnica [9.8K]

you would just add both of them together so the weight would be 7.69 Ibs

7 0

2 years ago

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

8 0

3 years ago