Answer:
line dancing, square dancing, etc
Step-by-step explanation:
1.) We can draw the height of triangle ORQ that intersects the center and we form right triangles. Using the definition of cosine, we get
cos x = (1/2) RQ / r
RQ = 2r cos x
2.) We simply use the expression for RQ we got from 1 to solve for the area of triangle ORQ. Similar to 1), the expression for the height of triangle ORQ is: r sin x.
For triangle POT, if we draw the height of the triangle that hits OP, we get special right triangles with angles 30-60-90. The height is simply twice that of the radius divided by the square root of 3.
So,
ratio of areas = (1/2)bh of triangle ORQ / (1/2)bh of triangle POT
b is the base and h is the height
ratio of areas = (1/2)(2r cos 75)(r sin 75) / (1/2)(r)(2/sqrt(3))(r)
ratio of areas = sqrt(3) / 8
the formula is f=(c*20)+30 so 14 degrees farhenhight
Answer:
c = 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
24 = 6c
<u>Step 2: Solve for </u><em><u>c</u></em>
- Divide 6 on both sides: 4 = c
- Rewrite: c = 4
<u>Step 3: Check</u>
<em>Plug in c to verify it's a solution.</em>
- Substitute in <em>c</em>: 24 = 6(4)
- Multiply: 24 = 24
Here we see that 24 does indeed equal 24.
∴ c = 4 is a solution of the equation.
Y=-5x+9
3x+2(-5x+9)=4
3x-10x+18=4
-7x=4-18
-7x=-14
x=2
5(2)+y=9
10+y=9
y=9-10
y=-1
The answer is (2,-1) :)