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Yanka [14]
3 years ago
6

There were 7 field goals made in 14 attempts. how many goals should be made in 8 attempts

Mathematics
2 answers:
vovikov84 [41]3 years ago
6 0
To get from 14 to 8, you divide by 7 and multiply by 4. Thus, if you divide 7 by 7 (1) and multiply it by 4 (4), you get 4 field goals in 8 attempts. Hope this helps!
trapecia [35]3 years ago
3 0
There would be 4

hope this helps you
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3 years ago
Solve y=f(x) for x. Then find the input when the output is -3.
DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

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now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

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And the real input is:

x=-\sqrt[3]{2}+5

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3 years ago
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