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Yanka [14]
3 years ago
6

There were 7 field goals made in 14 attempts. how many goals should be made in 8 attempts

Mathematics
2 answers:
vovikov84 [41]3 years ago
6 0
To get from 14 to 8, you divide by 7 and multiply by 4. Thus, if you divide 7 by 7 (1) and multiply it by 4 (4), you get 4 field goals in 8 attempts. Hope this helps!
trapecia [35]3 years ago
3 0
There would be 4

hope this helps you
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Given f(x) = 4x3 − 12x2 + 40x + 12, find f(–2). A) f(–2) = –52 B) f(–2) = –96 C) f(–2) = –108 D) f(–2) = –148
AURORKA [14]

Given function : f(x) = 4x^3 -12x^2 + 40x + 12.

We need to find the values of f(-2).

In order to find the value of f(-2), we need to plug x=-2 in the given fucntion f(x) = 4x^3 -12x^2 + 40x + 12.

Replacing x by -2, we get

f(-2) = 4(-2)^3 -12(-2)^2 + 40(-2) + 12

We get (-2)^2 = -2 *-2*-2=-8 and (-2)^2 = -2 * -2 = 4.

f(-2) = 4(-8) -12(4) +40(-2) +12 .

f(-2) = -32 -48 -80+12.

f(-2) = -160 +12.

f(-2) = -148.

Therefore, correct option would be option D. That is  f(-2)=-148.                



8 0
3 years ago
What is a = 1/2 (b-c) if b is the subject
natulia [17]

Answer:

b = 2a + c

Step-by-step explanation:

Given

a = \frac{1}{2} (b - c)

Multiply both sides by 2 to clear the fraction

2a = b - c ( add c to both sides )

2a + c = b

5 0
3 years ago
How many zeros does the function f(x) = 4x^11 − 20x^7 + 2x^3 − 15x + 14 have?
yulyashka [42]
Dont know yrrrrrr.........
6 0
3 years ago
Х
Vesna [10]

Answer: the answer is

(-2,0)

(0,2)

4 0
3 years ago
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What numbers add to 21 but equal 472
Anastaziya [24]
Hey there,

All we have to do is 472-21=451

So your number would be 451
8 0
3 years ago
Read 2 more answers
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