All categories

3 years ago

when using a counterexample to prove a conditional statement false, which must be true about the counterexample?

1 answer:

3 0

The science of correct reasoningLogicThe drawing of inferences or conclusions from known or assumed factsReasoningUses observations and patterns to arrive at a conclusion (conjecture)Inductive reasoningUses facts, rules, definitions, or properties to arrive at a conclusionDeductive reasoningA statement that can be written in if-then formConditional statementConditional statement symbol-->The opposite meaning of the original statementNegationsA statement, example, figure, etc... that proves that a statement is falseCounterexamplesIf you live in florida, then you live in miamiFalse; counterexampleWith counterexamples you should not correct the statement and give an example of why the statement is falseTrueAll true statement do have counterexamplesFalse they do notConditional symbolp-->qSwitch the hypothesis and conclusionConverseConditional and the converseBiconditional statementsJoins the conditional and converse into one statement<span>Bionditional statements</span>

You might be interested in

What numbers are a multiple of both 5 and 15

Aneli [31]

Answer: is 3

Step-by-step explanation: this is because you need to divide the two numbers and 3 go into 5 and 15.

4 0

3 years ago

Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.

marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}$

$\dfrac{a^m}{a^n} = a^{(m-n)}$

$\sqrt[m]{a^n} = a^{\frac{n}{m}}$

$(a^m)^n = a^{m\times n}$

$(m\times n)^a = m^a\times n^a$

The expression can be written as $x^9\sqrt[3]{y}$ .

Given to us

$(x^{27}y)^\frac{1}{3}$

$(x^{27}y)^\frac{1}{3}$

Using the exponential property $(m\times n)^a = m^a\times n^a$ ,

$=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}$

Hence, the expression can be written as $x^9\sqrt[3]{y}$ .

Learn more about Exponent properties:

brainly.com/question/1807508

5 0

2 years ago

Read 2 more answers

A figure is translated six units to the left and two units down. Which rule represents this translation?

Helga [31]

The answer would be d. because you’re moving back then moving downwards starting from 0 (the origin). Which would make x and y negative numbers.

8 0

1 year ago

Find an equation of the line described. Write the equation in slope-intercept form when possible. Through (2,9) and (0,0)

zheka24 [161]

Answer:

y=9/2x

Step-by-step explanation:

I used my notes.

5 0

2 years ago

To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before ad

Kryger [21]

Answer:

The first equation should be multiplied by 9 and the second equation by −4

Step-by-step explanation:

Given the simultaneous equation

First Equation: 5x − 4y = 28

Second equation: 3x - 9y = 30

In order to eliminate y, we must make the coefficient of x in both expression to be equal.

To do that the first equation should be multiplied by 9 (negative value of the coefficient of y in equation 2)and the second equation by -4( (coefficient of y in equation 1)

7 0

3 years ago