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2 years ago

What is the reciprocal of 3 1/5

Mathematics

2 answers:

damaskus [11]2 years ago

8 0

Answer:

5/16

Step-by-step explanation:

To find the reciprocal you have to make the fraction a mixed number by multiplying the denominator by the whole number then adding the numerator, in this case it would give you 16/5. Since the reciprocal is the number that you multiply to get one, if you switch the denominator and the numerator, you get 5/16.

You can check your work by multiplying the numbers together, if it equals one, your reciprocal is correct, if not, then you may have to do it again.

Talja [164]2 years ago

4 0

Answer:

5/16

Step-by-step explanation:

We need to change the mixed number to an improper fraction to find the reciprocal

3 1/5 = (5*3+1)/5 = 16/5

The reciprocal of 16/5 is found by flipping the fraction

5/16

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vlada-n [284]

Using it's concept, the range of function g is given by:

B. $\{y|y \in \mathbb{R}, y \neq -4, -3\}$

<h3>What is the range of a function?</h3>

The range of a function is the set that contains all possible output values for the function. In a graph, it is the values of y.

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1 year ago

What is the scale factor of the two triangles below?

irina [24]

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2 years ago

the width of a rectangle is the length minus 2 units. The area of the rectangle is48 units. What is the width, in units, of the

tatuchka [14]

Answer:

Step-by-step explanation:

put unknown as y

area of rectangle = width × long

y(y - 2)=48

y² -2y =48

u can use scientific calculator to find this

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I hope this help you :)

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2 years ago

Gertie ran 3/4 mile during physical education class. Sarah ran 2/4 mile during the same class. How much farther did Gertie run t

Marizza181 [45]

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3 years ago

Read 2 more answers

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Gre4nikov [31]

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$\frac{200}{60} = \frac{10}{3} \approx 3.33$ loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$\frac{200}{65} = \frac{40}{13} \approx 3.08$ loops per minute

then the period is:

$\frac{13}{40} =0.325\,\,\,minutes$

Therefore runner B has the smaller period

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2 years ago