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Blizzard [7]
4 years ago
14

I need the answer!!!!!!!

Mathematics
1 answer:
insens350 [35]4 years ago
7 0

Answer:

A

Step-by-step explanation:

It flips over the y-axis making the x negative

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At a factory, a machine puts tops on bottles at a rate of 90 bottles per minute. How many tops can be put on bottles between 10:
Mrac [35]

Answer:

  • 24300

Step-by-step explanation:

<u>Rate:</u>

  • 90 tops/min

<u>Time:</u>

  • 2:30 PM - 10:00 AM = 14:30 - 10:00 = 4:30 hours
  • 4:30 hours = 4*60 + 30 min = 270 min

<u>Number of tops can be put in 270 min:</u>

  • 270*90 = 24300
5 0
3 years ago
In degrees what is the measure of MFE<br> HELP PLS I AM TIMED
wolverine [178]

Answer:

ADD THEM AND THEN SUBSTRACT THE RWO NUMBER AND DIVIDE YOUR X!!

Step-by-step explanation:

5 0
3 years ago
Real talk shhhh
abruzzese [7]

Answer:

3

15. 8

Step-by-step explanation:

The man and the son form similar triangles, so the lengths of corresponding sides of the triangles are proportional.

6/8 = x/4

8x = 24

x = 24/8

x = 3

Answer: 3

Question 15

Triangles SCA and STR are similar, so the lengths of corresponding sides are in proportion.

SA + AR = SR

SA + 3 = 9

SA = 6

SA/SR = SC/ST

6/9 = SC/12

2/3 = SC/12

3SC = 2 * 12

3SC = 24

SC = 8

3 0
3 years ago
Pleeease answer! Tysm!
yulyashka [42]

Answer:

The answer is 9 1/15 aka answer A.

Step-by-step explanation:

Too lazy to explain. :p

3 0
4 years ago
The focal lengths of the objective lens and the eyepiece of a microscope are 0.50 cm and 2.0 cm, respectively, and their separat
VladimirAG [237]

Answer:

- 103.7

Step-by-step explanation:

Given:

Focal length of the eyepiece, f = 2.0 cm

Focal length of the objective lens, f' = 0.50 cm

Separation for minimum eyestrain = 6,0 cm

Image distance, v = - 25 cm

Now, from the lens formula,

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

here, u is the object distance

on substituting the respective values, we get

\frac{1}{2}=\frac{1}{u}+\frac{1}{-25}

or

u = 1.852 cm

also, the separation is adjusted for minimum eyestrain,

therefore, image distance for the objective lens, v' = 6 - 1.852 = 4.148 cm

Now, for the objective lens

using the lens formula, we get

\frac{1}{0.5}=\frac{1}{u'}+\frac{1}{4.418}

Here, u' is the distance between the physical object and objective lens

or

u' = 0.568 cm

Thus,

Magnification, m = -\frac{vv'}{ff'}

or

m =-\frac{25\times4.418}{0.5\times2}

or

m = - 103.7

4 0
3 years ago
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