The angle of elevation from a viewer to the center of a fireworks display is 55°. If the viewer is 75 yards away from where the

Question

marusya05 [52]

2 years ago

13

The angle of elevation from a viewer to the center of a fireworks display is 55°. If the viewer is 75 yards away from where the

fireworks are launched, at what height is the center of the display? Round to the nearest whole yard

Mathematics

1 answer:

notka56 [123] · Answer 1 · 2022-09-10T07:35:00+03:00

Answer:

107.1075 yards

Step-by-step explanation:

To solve this problem, we can imagine a triangle, where one of the angles is 55 degrees, the adjacent cathetus is 75 yards, and we want to know the opposite cathetus (the height of the center of the display, "h").

The relation between opposite and adjacent cathetus is the tangent, so:

tan(55) = h/75

tan(55) = 1.4281, so:

h/75 = 1.4281

h = 75*1.4281 = 107.1075 yards