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marusya05 [52]
2 years ago
13

The angle of elevation from a viewer to the center of a fireworks display is 55°. If the viewer is 75 yards away from where the

fireworks are launched, at what height is the center of the display? Round to the nearest whole yard
Mathematics
1 answer:
notka56 [123]2 years ago
5 0

Answer:

107.1075 yards

Step-by-step explanation:

To solve this problem, we can imagine a triangle, where one of the angles is 55 degrees, the adjacent cathetus is 75 yards, and we want to know the opposite cathetus (the height of the center of the display, "h").

The relation between opposite and adjacent cathetus is the tangent, so:

tan(55) = h/75

tan(55) = 1.4281, so:

h/75 = 1.4281

h = 75*1.4281 = 107.1075 yards

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x\dfrac{\mathrm dy}{\mathrm dx}-y=x^2\sin x

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\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1xy\right]=\sin x
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- - -

The second equation is also linear:

x^2y'+x(x+2)y=e^x

Multiply both sides by e^x to get

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(x^2e^xy)'=e^{2x}
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- - -

Yet another linear ODE:

\cos x\dfrac{\mathrm dy}{\mathrm dx}+\sin x\,y=1

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- - -

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