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marusya05 [52]
3 years ago
13

The angle of elevation from a viewer to the center of a fireworks display is 55°. If the viewer is 75 yards away from where the

fireworks are launched, at what height is the center of the display? Round to the nearest whole yard
Mathematics
1 answer:
notka56 [123]3 years ago
5 0

Answer:

107.1075 yards

Step-by-step explanation:

To solve this problem, we can imagine a triangle, where one of the angles is 55 degrees, the adjacent cathetus is 75 yards, and we want to know the opposite cathetus (the height of the center of the display, "h").

The relation between opposite and adjacent cathetus is the tangent, so:

tan(55) = h/75

tan(55) = 1.4281, so:

h/75 = 1.4281

h = 75*1.4281 = 107.1075 yards

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MAXImum [283]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m represents the slope of the line

c represents the y intercept

The equation of the given line is

2x + 4y = 20

4y = - 2x + 20

Dividing through by 4, it becomes

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Comparing with the slope intercept form, slope = - 1/2

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To determine the y intercept, we would substitute m = - 1/2, x = - 6 and y = 3 into y = mx + c. It becomes

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3 years ago
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jek_recluse [69]

Answer:

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Step-by-step explanation:

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2 years ago
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bogdanovich [222]

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Step-by-step explanation:

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In this truss bridge, AAOB ABDC. AO=5 meters, BD=10 meters, AB=5 meters. What is the length of BC? A. 5 m B. 8 m C. 10 m D. 15 m
Olenka [21]

Consider \Delta AOB\cong \Delta BDC.

Given:

\Delta AOB\cong \Delta BDC, AO=5\ m,BD=10\ m, AB=5\ m.

To find:

The length of BC.

Solution:

We have,

\Delta AOB\cong \Delta BDC

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AB=BC                   (CPCTC)

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