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Pachacha [2.7K]
3 years ago
16

The graph of the piecewise function f(x) is shown what is the domain of f(x)

Mathematics
1 answer:
Rom4ik [11]3 years ago
8 0

The domain of a function is where we have a value for x.

Since that's the case the domain of f(x) = {x e R / 1 ≤ x < 5}

We see that we have a value for x = 1 cuz we have a filled circle, but we don't have a value for x = 5, look at the unfilled circle

So, our x can vary between 1 and 5, but can't be 5.

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Kelly inherits land which had a basis to the decedent of $95,000 and a fair market value of $50,000 on August 4, 2018, the date
Degger [83]

Answer:

The correct option is;

Her recognized <u>loss </u>is ($1,000)

Step-by-step explanation:

The given information are;

The basis of the land to the decedent = $95,000

The land's market value on 4th of August 2018 when the decedent died  = $50,000

The alternate valuation date = 6 months + The date of death of the decedent = 4th February, 2019

The value filed by the executor on the tax return using the alternate valuation date = The market value of the estate on 4th of February 2019

The market value of the land on 4th of February 2019 = $45,000

∴ The value filed by the executor on the tax return using the alternate valuation date = $45,000

The value of the land on November 12, 2018 when the executor distributed the land to Kelly = $49,000

The value at which Kelly sells the land on June 10, 2019 = $48,000

Given that, recognized gain is the profit made from selling an asset based on the value of the asset when it was obtained, we have;

Kelly's recognized gain or loss = (The value at which Kelly sells the land) - (The value of the land when the executor distributed the land to Kelly)

Kelly's recognized gain or loss = $48,000 - $49,000 = -$1,000 = ($1,000)

Therefore, Kelly's recognized loss = ($1,000).

6 0
3 years ago
Evaluate this pls quiick i have 18 min left online exams help<br><br> -0.0004 x 0.02
lions [1.4K]

Given:

The expression is:

0.0004\times 0.02

To find:

The value of the given expression.

Solution:

We have,

0.0004\times 0.02

It can be written as:

=\dfrac{4}{10000}\times \dfrac{2}{100}

=\dfrac{8}{1000000}

=0.000008

Therefore, the value of the given expression is 0.000008.

3 0
3 years ago
FOR 12 POINTS I NEED HELP ASAP! Consider the system of linear equations. 5 x + 10 y = 15. 10 x + 3 y = 13 To use the linear comb
Romashka [77]

Answer:

Do you mean which equation should the 5x+10=15 be multiplied to?

it would be -2

Step-by-step explanation:

This is because 5 times -2 is -10

and so when you add the (now) x value of the first equation to the x value of the second equation, it gets 0

which makes it eliminated!

-10x+10x=0

8 0
3 years ago
In the data set below, what is the mean absolute deviation?4461526If the answer is a decimal, round it to the nearest tenth.mean
bixtya [17]
I assume that the numbers are: 4,4,6,1,5,2,6
If so, then the MAD is 1.43

To find the MAD, you first find the mean of the list. It is 4.
Then find the absolute difference of each number from the mean.

Those values are: 0,0,2,3,1,2,2
Now find the mean of those numbers and you have about: 1.43
5 0
3 years ago
I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

4 0
3 years ago
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