Step-by-step explanation:
i was busy so i did this much ...will solve later
Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
Answer:
1.92%
Step-by-step explanation:
The probability for first case, picking a queen out of deck, will be:
as there will be 4 queens in a deck, one of each suit.
For the second pick, the probability of picking a diamond card, will be:
here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).
Thus the net probability for both cases will be:
Thus total probability for the combined two cases will be 1.92%
The Pythagorean Theorem is a^2 +b^2 = c^2, where a and b are the sides and c is the hypotenuse ( angled line).
3.
a^2 + 6^2 = 18^2
a^2 + 36 = 324
a^2 = 324 - 36
a^2 = 288
a =√288
a = 12√2
4.
a^2 + 3^2 = 9^2
a^2 + 9 = 81
a^2 = 81-9
a^2 = 72
a = √72
a = 6√2
