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tatuchka [14]
4 years ago
14

An airplane needs to reach a velocity of 203.0 km/h to take off. On a 2000 m runway, what is the minimum acceleration necessary

for the plane to take flight?
Mathematics
1 answer:
Aliun [14]4 years ago
6 0

Answer:

1.59 m/s²

Step-by-step explanation:

Acceleration = change in Velocity over time. Mathematically it is represented as Δv/Δt

Given values in the question:

  • Final velocity 203.0 km/h which is equal to (203/3.6)m/s = 56.39 m/s
  • distance 2000 m
  • Initial velocity is 0 m/s

<em>To use the equation for acceleration time is needed.</em>

<em>velocity= distance/time</em>

(203/3.6) = 2000/time  <em>mltiplying both sides by time</em>

(203/3.6) x time = 2000 <em>making time subject of the formula</em>

time = 2000/(203/3.6)

time = 35.47 seconds

Substituting into the acceleration equation

acceleration =Δv/Δt

                      =(56.39- 0)/35.47

                       = 56.39/35.47

                       =1.59 m/s²

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Answer:

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Step-by-step explanation:

The given triangle is a right angled triangle.

So, the angles in the triangle are :

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Solving according to <u>angle sum property</u>,

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