Relationship B is represented by B. So C and D are both correct.
So the original price is "x".
the discounted price by 10% is P(x) = 0.9x.
the price minus a $150 coupon is C(x) = x - 150.
so, if you go to the store, the item is discounted by 10%, so you're really only getting out of your pocket 90% of that, or 0.9x, but!!! wait a minute!! you have a $150 coupon, and you can use that for the purchase, so you're really only getting out of your pocket 0.9x - 150, namely the discounted by 10% and then the saving from the coupon.
C( P(x) ) = P(x) - 150
C( P(x) ) = 0.9x - 150
Hmm
what you do is try to eliminate 1 variable in 2 equaions first
we can elminate x's in first and 2nd equation
add first and 2nd equation
x+3y-2z=10
<u>-x-2y+z=-7 +</u>
0x+y-z=3
y-z=3
multiply 2nd equation by 3 and add to last one
-3x-6y+3z=-21
<u>3x+9y-5z=28 +</u>
0x+3y-2z=7
3y-2z=7
we now have
y-z=3
3y-2z=7
multiply first equation by -2 and add to 2nd
-2y+2z=-6
<u>3y-2z=7 +</u>
y+0z=1
y=1
now we can sub back
y-z=3
1-z=3
minus 1
-z=2
times -1
z=-2
sub baack into any equation
x+3(1)-2(-2)=10
x+3+4=10
x+7=10
minus 7
x=3
x=3
y=1
z=-2
(3,1,-2)
8n+10=50 <-- Original Equation
8n=40 <-- Use the Subtraction Property of Exponents to remove the 10 from the left
n=5 <-- Use Division Property of Exponents to remove the 8 from the n and find the unit of n
The number of bracelets Larina can purchase is five.
Answer:
case A. 
case B. 
case E. 
Step-by-step explanation:
we have
we know that
<u>Verify each case</u>
case A)
therefore
is equivalent to
case B)
so
is equivalent to
case C) 
therefore
is not equivalent to
case D) 
so
is not equivalent to
case E)
therefore
is equivalent to
case F) 
so
is not equivalent to
