The value of the lower class limit of the 3rd class is; 11.0
<h3>What is the lower class Interval?</h3>
The lower class limit is lowest value of that class interval while upper class limit is highest value of that class interval.
Hours Number of Students
0.0–5.4 12
5.5–10.9 16
11.0–16.4 14
16.5–21.9 11
22.0–27.4 6
Now, the third class interval is 11.0–16.4 and from definition of lower class limit, we can say that the lower class limit of the 3rd class is; 11.0
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1,296.0 I think this is right, I apologize if it’s wrong.
Answer:
y = -5/4x + 3
Step-by-step explanation:
Answer:

Step-by-step explanation:
Let m denotes the number of minutes of phone use in a month.
In plan a there is no monthly fee, but the customer pays 8 cents per minute of use.
Total cost of plan a = 
In Plan B the customer pays a monthly fee of $2.40 and then an additional 7 cents per minute of use.
Total cost of plan b = 
To find amount of monthly phone use for which plan a cost more than plan b, solve the inequality
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I think it is a 95 % you pick a apple or a peach because you won’t know I till you look at it