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Archy [21]
3 years ago
7

On a coordinate plane, a line goes through (0, negative 1) and (3, 1). A point is at (negative 3, 0).

Mathematics
2 answers:
tatiyna3 years ago
5 0

Answer: y = (2/3)x + 2

Step-by-step explanation: We have a line that passes trough the points (0, -1) and (3, 1)

The slope of this line that passes trough the points (x1,y1) and (x2,y2) is:

s = (y2 - y1)/(x2 - x1)

s = ( 1 - (-1))/(3 - 0) = 2/3

So we know that this line has the shape:

Y1(x) = 2/3x + b

where b is the y intercept.

In order to find the value of b, we can do:

Y1(0) = -1 = (2/3)*0 + b = b

so we have that b = -1, and the equation of the line is:

y1(x) = (2/3)*x - 1

Now, we want to find another parallel line that passes through the point (-3,0)

because this new line is parallel to the one we previous had, their slopes must be equal, then the equation of our new line is:

Y2(x)= (2/3)x + c

and we need to find the value of c.

Y2(-3) = 0 = (2/3)*-3 + c = -2 + c = 0

c = 2

then the equation is:

Y2(x) = (2/3)x + 2

Bingel [31]3 years ago
5 0

Answer:

c

Step-by-step explanation:

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Which relation does not represent a function​
Nastasia [14]

Answer:

For example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.

Hope this helped

3 0
2 years ago
5. Carlotta's Beauty Supply store sells two brands of bar soap. A 6 pack of Brand A costs
vekshin1
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3 years ago
30 ounce box of cerebral contains 12 servings
gulaghasi [49]

Answer:

okay?

Step-by-step explanation:

is that supposed to be like is that true or false or am I just not understanding if that's a question or not

8 0
3 years ago
Read 2 more answers
3|3t+1|=2|6t+3| Need hep
mars1129 [50]

Answer:

your answer would be  t=-1 or t=1

Step-by-step explanation:

-(2t-3) = 3t-2

Multiply

     -2t+3 = 3t-2

Rearrange and Add up

     -5t = -5

Divide both sides by 5

-t = -1

Multiply both sides by (-1)

t = 1

Which is the solution for the Negative Case

Solve the Positive Case

     (2t-3) = 3t-2

Rearrange and Add up

     -t = 1

Multiply both sides by (-1)

     t = -1

have a great day!

4 0
3 years ago
Find the minimum and maximum value of the function on the given interval by comparing values at the critical points and endpoint
Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) =  √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0)  =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

g(x) = 1 + x^2 - 2x

Then:

f(x) = h(g(x))

f'(x)  =  1/2*( 1 + x^2 - 2x)*(2x - 2)

f'(x) = (1 + x^2 - 2x)*(x - 1)

f'(x) = x^3 - 3x^2 + x - 1

this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

Then the maximum and minimum are given by the endpoints.

The maximum is 1 (when x = 0)

the minimum is 0 (when x = 1)

7 0
3 years ago
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