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qwelly [4]
3 years ago
7

PLLLLSSSS HELPP IM MARKING BRAINLIEST

Mathematics
2 answers:
Anna007 [38]3 years ago
7 0
W(x) is giving you the normal usage, D(x) is telling you by how much W(x) decreases. To find out what the actual usage is after the decrease we are going to have to subtract D(x) from W(x). I’m going to attach an image of how I did that, but basically your just subtracts the coefficients (number in front) where the exponents are the same. Also, don’t forget that since there is no x in D(x) we add in a +0X as a place holder.
I ended up with C(x)=2X^3+2X^2-18X-11 (option 1) Let me know if you have any questions.

Temka [501]3 years ago
3 0

Answer:

A C(x) =2x³+2x²-18x-11

Step-by-step explanation:

C(x) = W(x) - D(x)

plug W(x) and D(x) into equation

C(x) = 3x³+4x²-18x+4 - (x³+2x²+15)

add like terms now

C(x) =2x³+2x²-18x-11

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The probability that Scott will win his next tennis match is 3/5
goblinko [34]

Answer:

the probability that he will not win is 2/5 cause it's just the chance that he doesn't win

6 0
3 years ago
The radioactive substance polonium-210, with a half-life of 138.39 days, is present in tobacco. Suppose that the soot in an ex-s
Ksju [112]

Answer:

16.07 milligrams

Step-by-step explanation:

From the question,

Using the formula of radioactive decay,

R/R' = 2ᵃ/ᵇ..................... Equation 1

Where R = Original mass of the polonium-210, R' = Final mass of polonium-210 after decaying, a = Total disintegration time, b = half life of polonium-210.

Make R' the subject of the equation

R' = R/(2ᵃ/ᵇ)................ Equation 2

Given: R = 100 milligrams, a = 1 years = 365 days, b = 138.39 days

Substitute these values into equation 2

R' = 100/(2³⁶⁵⁰⁰/¹³⁸³⁹)

R' = 100/(6.222)

R' = 16.07 milligrams of plonium-210

3 0
3 years ago
Examine this system of equations. Which number can be multiplied by each equation so that when the two equations are
andreyandreev [35.5K]

Answer:

15 times the first equation and -12 times the second equation

Step-by-step explanation:

we have

\frac{3}{4}x+\frac{2}{3}y=6 ------> first equation

\frac{5}{8}x+\frac{5}{6}y=12 ------> second equation

Multiply the first equation by 15 both sides

(15)\frac{3}{4}x+(15)\frac{2}{3}y=6(15)

\frac{45}{4}x+10y=90 -----> new first equation

Multiply the second equation by -12 both sides

(-12)\frac{5}{8}x+(-12)\frac{5}{6}y=12(-12)

-\frac{60}{8}x-10y=-144 -----> new second equation

Adds the two new equations

\frac{45}{4}x+10y=90\\-\frac{60}{8}x-10y=-144\\-----------\\\frac{45}{4}x-\frac{60}{8}x=90-144

The y-term was eliminated

5 0
3 years ago
Select the relations that are functions.
liraira [26]

Answer:

option A, C  and D

Step-by-step explanation:

Each relation is a function if each input has only one output

{a, 1), (6, 1), (C, 1)

This relation is a function because each input has only one output

{a, a),(a, b),(a, c)}

This relation is not a function because input 'a' has only three output

{(1, a), (2, a),(3, a)}

This relation is a function because each input has only one output

{a, a), (b, b), (C, c)}

This relation is a function because each input has only one output

7 0
3 years ago
Malik's arts and crafts shop has a bolt of crimson velvet 32 meters long. A customer came in during the morning and bought 120 c
kaheart [24]
Mil seiscientos ochenta,centímetros; le quedan a La tienda Malik’s. 3200-1520=1680 cm
6 0
3 years ago
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