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marshall27 [118]
3 years ago
15

-72 = 8d what does d equal

Mathematics
2 answers:
finlep [7]3 years ago
7 0
-9 will be the answer to the problem
snow_tiger [21]3 years ago
6 0
D=  -9  b/c -72/8=-9

hope this helps


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What are the intercepts of this function f(x)=-8x+4
Sidana [21]

Answer:

Step-by-step explanation:

to find the x-intercept:

Make y=0

0=-8x+4

8x =4

x=4/8

x=1/2

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Make x=0

y=-8(0) +4

y=4

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The equation F=
tensa zangetsu [6.8K]

Answer:62

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3 years ago
Find the surface area of composite figure. use 3.14 for π. round to the nearest tenth
ExtremeBDS [4]

Combining of the two cylinders gives a composite figure that has the surface area of a solid cylinder of radius 7 mm and height 6 mm, such that the surface area of the figure is approximately 571.5 mm².

<h3>Which method can be used to find the surface area of the figure?</h3>

Radius of the inner cylinder, <em>r</em> = 3 mm

Radius of the outer cylinder, <em>R</em> = 7 mm

Height of the cylinders, <em>h</em> = 6 mm

Given that the inner cylinder exactly fits into the outer cylinder, we have;

The surface area of the composite figure is the surface area of the hollow outer cylinder + The area of the top and bottom of the inner cylinder.

Which gives;

The surface area of the composite figure, <em>A</em>, is the surface area of a solid cylinder, using the dimensions of the hollow outer cylinder.

  • A = 2•π•R² + 2•π•R•h

Which gives;

  • A = 2 × π × 7² + 2 × π × 7 × 6

Where, π = 3.14, we have;

A = 2 × 3.14 × 7² + 2 × 3.14 × 7 × 6 ≈ 571.5

  • The surface area of the composite figure, <em>A </em>≈ 571.5 mm²

Learn more about the analyzing of composite figures here:

brainly.com/question/21135654

#SPJ1

4 0
2 years ago
If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in
Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume (V), in cubic centimeters, and surface area (A_{s}), in square centimeters, of the box with a square base are described below:

A_{s} = l^{2}+h\cdot l (1)

V = l^{2}\cdot h (2)

Where:

l - Side length of the base, in centimeters.

h - Height of the box, in centimeters.

By (2), we clear h within the formula:

h = \frac{V}{l^{2}}

And we apply in (1) and simplify the resulting expression:

A_{s} = l^{2}+ \frac{V}{l}

A_{s}\cdot l = l^{3}+V

V = A_{s}\cdot l -l^{3} (3)

Then, we find the first and second derivatives of this expression:

V' = A_{s}-3\cdot l^{2} (4)

V'' = -6\cdot l (5)

If V' = 0 and A_{s} = 30000\,cm^{2}, then we find the critical value of the side length of the base is:

30000-3\cdot l^{2} = 0

3\cdot l^{2} = 30000

l = 100\,cm

Then, we evaluate this result in the expression of the second derivative:

V'' = -600

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

V = 30000\cdot l - l^{3}

V = 2000000\,cm^{3}

The largest possible volume of the box is 2000000 cubic meters.

4 0
3 years ago
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