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2 years ago

If one gallon is the same amount as 4 quarts, how many quarts are in 5 gallons?

Mathematics

2 answers:

MatroZZZ [7]2 years ago

8 0

Answer:

It's just 20 quarts

Step-by-step explanation: :/

it's just 20 quarts

wlad13 [49]2 years ago

6 0

If one gallon = 4 quarts
Then 5 gallons = x quarts

To solve this we can set up a porportion

1/4 = 5/x

To solve the porportion we need to find the rule so how to we get to 4 from 1? Well we can multiply 1 by 4 to get one right?

So if this is true, 1 x 4 = 4 then 5 x 4 must equal x

5 x 4 = 20 so the answer would be 20 quarts are in 5 gallons

Another way to look at this is that you have 5 gallons and in each gallon is 4 quarts to if there is 4 quarts in every one gallon then that’s just 4 + 4 + 4 + 4 + 4 or 5 x 4

I hope this helps! <3

So i

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2 years ago

A grocery store sells Swiss cheese for $5.90 a pound. To the nearest cent, what is the cost per ounce of Swiss cheese? Round you

Debora [2.8K]

Answer:

37 cents

Step-by-step explanation:

Given that a grocery store sells Swiss cheese

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3 years ago

jo divides a rectangle into parts. each part is 1/4 the area of the whole rectagle. how many parys did ko divide the rectanhle i

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2 years ago

Read 2 more answers

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

2 years ago

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Nesterboy [21]

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Step-by-step explanation:math

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2 years ago