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ella [17]
3 years ago
10

_____ allows companies to offer people personalized content based on their interests or shopping experience.

SAT
1 answer:
Lisa [10]3 years ago
7 0
The answer is A, tracking.
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The ACT reading test covers all of the following except:
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A theorem in geometry states that the measure of an inscribed angle is half the measure of its intercepted arc.

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A survey showed that 34 ​% of human resource professionals are at companies that rejected job candidates because of information
Svetllana [295]

Using the binomial distribution, it is found that since 16 is more than 2.5 standard deviations above the mean, it is a unusually high number.

<h3>What is the binomial probability distribution?</h3>

It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

A measure is considered to be unusually high if it is more than 2.5 standard deviations above the mean.

In this problem, we hav ehtat:

  • 34% of companies reject candidates because of information found on their social media, hence p = 0.34.
  • 27 human resource professionals are randomly​ selected, hence n = 27.

Then, we find the threshold for unusually high values as follows:

E(X) = np = 27 x 0.34 = 9.18

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{27(0.34)(0.66)} = 2.46

T = 9.18 + 2 x 2.46 = 14.1.

Since 16 is more than 2.5 standard deviations above the mean, it is a unusually high number.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

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2 years ago
In the country of United States of Height, the height measurements of ten-year-old children are approximately normally distribut
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Answer:

a) We need to find p(x<68.15)

Standardize x to z, we have, z = (68.15-μ)/σ

=(68.15-57)/8.1

=1.38

Reading from standard normal tables,

p(z<1.38) =0.9162.

b) We need to find p(x>54.4)

Standardize x to z, we have, z = (54.4-μ)/σ

=(54.4-57)/8.1

=-0.32

Reading from standard normal tables,

p(z>-0.32) = 0.6255

7 0
1 year ago
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