Question

How many total atoms are present in 32. 8 grams of cu2s?.

Answer 1

0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.

Total atoms in a compound

Given the following parameters

• Mass of  Cu2s = 32.8 grams

Get the number of moles

• Moles = Mass/Molar mass

Moles = 32.8/159.16 g/mol

Moles of Cu2S = 0.240moles

Since 1 molecule of atom  = 6.02 * 10^23 molecules

Hence 0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.

Learn more on molecules of compound here: brainly.com/question/473667

Answer 2

The number of atoms that are present in 32.8 grams of Cu2S is; 1.235 × 10²³ atoms

Number of atoms and Avogadro's number

The molar mass of Cu2S is; 64 +64 + 32

Hence, molar mass = 160.

Hence, the no. if moles in 32.8 grams of Cu2S is;

• No. of moles, n = 32.8/160

• n = 0.205.

Hence, the no. of atoms in the given sample is;

• No. of atoms = n × Avogadro's number

• No of atoms = 0.205 × 6.022 × 10²³

No. of atoms = 1.235 × 10²³ atoms

Read more on Avogadro's number;

brainly.com/question/1528951