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3 years ago

Which quadratic equation is equivalent to (x+2)^2+5(x+2)-6=0?

Mathematics

2 answers:

Mrrafil [7]3 years ago

8 0

U=(x+2)
u^2+5u-6=0

C is answer

zepelin [54]3 years ago

6 0

C. is the correct answer to this question

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3 years ago

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2 years ago

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Answer:

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2 years ago

Can you answer #1 and #3 please (find the slope) ASAP

daser333 [38]

To calculate the slope of a line, you only need two points from that line, (x1, y1) and (x2, y2).

The equation used to calculate the slope from two points is:

(y2 - y1) / (x2 - x1)

#1:

First point : (5 ,7) = (x1, y1)

Second point : (2, -2) = (x2, y2)

Equation : (-2 - 7) / (2 - 5)

Solve the equation:

(-2 - 7) = -9

(2 - 5) = -3

-9/-3 = 3 (a negative number divided by a negative number gives you a positive number)

The slope of the line in #1 is : 3

#3:

First point : (5, 9) = (x1, y1)

Second point : (5, -2) = (x2, y2)

Equation : (-2 - 9) / (5 - 5)

Solve the equation:

In this case, you don't need to solve anything, because anything divided by zero will give you 0 (5 minus 5 = 0).

The slope of the line in #3 is : 0

8 0

3 years ago

Read 2 more answers

Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

Read 2 more answers