Examine today’s stock listing for SFT Legal, shown below.
2 answers:
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Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable:
Therefore,
Variance of binomial random variable:
Therefore,
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Answer:
3rd option
Step-by-step explanation:
Using the identities
cot x =
csc² x = 1 + cot² x
Given
tanθ = , then cotθ =
csc²θ = 1 + ( )² = 1 +
=
cscθ = ± = ±
Since θ is in 3rd quadrant, then cscθ < 0
cscθ = - ×
= -
Answer:
Step-by-step explanation:
Distribute negative sign.
Combine like terms.