So average is of the first 6 tests is 82 well that means
(test1 + test2+ test3+ test4 + test5+test6)/6 = 82
so now let do some cross multiplliying
test1 + test2 + test3 + test 4 + test5 +test6 = 82*6
test1 + test2 + test3 + test 4 + test5 +test6 = 492
now lets see if we can find that 7th test score
(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5
So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute.
(492 + test7 )/7 = 80.5
test7 = (80.5*7)-492 = 71.5
Example of linear equation:
Let's have the linear equation;
<h3 /><h3>Put x=1</h3>
<h3>Put x=2</h3>
<h3>Put x=3</h3>
Find the factors of 16 and -24
16 = 8 x 2
-24 = 8 x -3
Note that both terms have "a" in it. Factor a out too
Answer:
8a(2 - 3b)
hope this helps
<h3>
- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>
➷ Turn into improper fractions:
8/3 + 5/3
Now just add them:
13/3 or 4 1/3
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
