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Sliva [168]
4 years ago
8

1.Graph the function y=2/x . Find the range of the function given that the domain of the function is all real numbers x, except

x is not equal to 0. Draw a chart to show at least four ordered pairs that are on the graph.
Mathematics
1 answer:
Ivanshal [37]4 years ago
5 0
The range of the function is all real number values of y except y = 0.

Ordered pairs in the graph includes (-4, -0.5), (-2, -1), (-1, -2), (1, 2)
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Put the number that the decimal is over the place that it is in
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so .5 is in the tenths place so the fraction would be 5/10
the decimal is now converted into a fraction

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4 years ago
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Step-by-step explanation:

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3 years ago
Find an​ nth-degree polynomial function with real coefficients satisfying the given conditions.
lesya692 [45]

Answer:

\displaystyle f(x) = -2(x-2)(x^2+4)

Step-by-step explanation:

We want to find a third degree polynomial with zeros <em>x </em>= 2 and <em>x</em> = 2i and f(-1) = 30.

First, note that by the Complex Root Theorem, since <em>x</em> = 2i is a root, <em>x</em> = -2i must also be a root.

Hence, we will have the three factors:

\displaystyle f(x) = a(x-(2))(x-(2i))(x-(-2i))

Where <em>a</em> is the leading coefficient.

Expand and simplify the second and third factors:

\displaystyle \begin{aligned} (x-(2i))(x-(-2i)) &= (x-2i)(x+2i) \\ \\ &= x(x-2i)+2i(x-2i) \\ \\ &= (x^2 - 2ix) + (2ix - 4i^2) \\ \\ &=x^2 + 4\end{aligned}

Hence:

\displaystyle f(x) = a(x-2)(x^2+4)

Since f(-1) = 30:

\displaystyle \begin{aligned}  f(x) &= a(x-2)(x^2+4) \\ \\ (30) &= a((-1)-2)((-1)^2+4) \\ \\ 30 &= -15a \\ \\ a&= -2\end{aligned}

In conclusion, third degree polynomial function is:

\displaystyle f(x) = -2(x-2)(x^2+4)

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3 years ago
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Gwen says that the sum of -1 3/4 and 2 1/2 is the same as the difference between 2 1/2 and 1 3/4. Is Gwen correct? Explain why o
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Answer: No

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