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Likurg_2 [28]
3 years ago
5

Two numbers differ by 9. the large number is 20 greater than half of the smaller number. find the two numbers

Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0
Using x to represent the larger number and y to represent the smaller number, do this:
x - y = 9
x = 1/2y + 20
(1/2y + 20) - y = 9
(1/2y - y) + 20 = 9
-1/2y + 20 = 9
         -  20  - 20
-1/2y = -11
Divide each side by -1/2 to find y
y = 22
Plug the y value into the first equation
x - 22 = 9
  + 22 + 22
x = 31

The larger number is 31 and the smaller number is 22
yanalaym [24]3 years ago
6 0
Large = 20+ 1/2 of small and,

Large-small =9 so if we put back the 9 to the small one will get the large number
Large=9+small

Now we can see that
20+small/2 =9+ small
20-9=small-small/2
11=half of small so small is 22

Large = 20 + 11=31
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Step-by-step explanation:

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Your correct answer is: B

8 0
3 years ago
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Rudiy27

ok distribute the 6 by multiplying it by 1q and -5
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7 0
3 years ago
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Rzqust [24]

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Step-by-step explanation:

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3 0
3 years ago
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Answer:

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7 0
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