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Likurg_2 [28]
3 years ago
5

Two numbers differ by 9. the large number is 20 greater than half of the smaller number. find the two numbers

Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0
Using x to represent the larger number and y to represent the smaller number, do this:
x - y = 9
x = 1/2y + 20
(1/2y + 20) - y = 9
(1/2y - y) + 20 = 9
-1/2y + 20 = 9
         -  20  - 20
-1/2y = -11
Divide each side by -1/2 to find y
y = 22
Plug the y value into the first equation
x - 22 = 9
  + 22 + 22
x = 31

The larger number is 31 and the smaller number is 22
yanalaym [24]3 years ago
6 0
Large = 20+ 1/2 of small and,

Large-small =9 so if we put back the 9 to the small one will get the large number
Large=9+small

Now we can see that
20+small/2 =9+ small
20-9=small-small/2
11=half of small so small is 22

Large = 20 + 11=31
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You can try them out and see which one works.

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b: f(1) = f(2) -6 = -1-6 = -7 . . . . . . not this one (5 ≠ -7)

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_____

The appropriate choice is ...

... f(n +1) = f(n) - 6

— — — — — 

You can also recognize that the next term is 6 less than the current one, so f(n+1) = f(n) - 6, which corresponds to the 3rd selection.

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Answer:

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Step-by-step explanation:

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