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svetlana [45]
3 years ago
11

Dave won a hot dog eating contest by eating 18 hot dogs in 10 minutes. He ate two more than twice the amount of the runner-up. W

hich equation, when solved for x, gives the number of hot dogs the runner-up ate? A) 2x − 2 = 18 B) 2x + 2 = 18 C) x 2 − 2 = 18 D) x 2 + 2 = 18
Mathematics
2 answers:
IrinaVladis [17]3 years ago
8 0

Answer:

The correct anser is option

B. 2x + 2 = 18

Step-by-step explanation:

Let the number of hot dogs eaten by the runner up be represented by x

If Dave ate 2 more than twice x, this means that the number eaten by him = 2x + 2

Since the total number of hot dogs eaten by Dave is 18

Therefore, the equation will be

2x + 2 = 18

So the number of hot dogs eaten by the runner-up is determined by solving for x

2x= 18-2

2× = 16

x = 16/2

x = 8

The runner up are 8

While Dave are

2×8 + 2 = 18.

stira [4]3 years ago
3 0

Answer:

When solved for x, the runner-up ate 2x + 2 = 18

Step-by-step explanation:

Dave won by eating 18 hot dogs

He ate two more than twice the amount of the runner-up.

Suppose the runner-up ate x-hot dogs.

That means Dave ate two more than twice of x. This can be written as

Twice of x is 2x

And two more than twice of x is 2x + 2.

So, Dave ate (2x + 2) hot dogs.

Since we already know that Dave ate 18, we can say

2x + 2 = 18

2x = 16

x = 8

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Answer:

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1) Divide 230 by 48

4.791666666666667

2) multiply 4.791666666666667 by 33.6

161

Done! Your answer is 161 calories in a 33.6 gram bag. Or just 161.

Hope this helps!

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Carlos wants to buy a new t.v. He is willing to spend less than $600 for 36” or smaller or more than $2000 for 42” or larger. He
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3 years ago
Consider all 5 letter "words" made from the full English alphabet. (a) How many of these words are there total? (b) How many of
VARVARA [1.3K]

Answer:

a) There are 11,881,336 of these words in total.

b) There are 7,893,600 of these words with no repeated letters.

c) 896,376 of these words start with an a or end with a z or both

Step-by-step explanation:

Our words have the following format:

L1 - L2 - L3 - L4 - L5

In which L1 is the first letter, L2 the second letter, etc...

There are 26 letters in the English alphabet.

(a) How many of these words are there total?

Each of L1, L2, L3, L4 and L5 have 26 possible options.

So there are 26^{5} = 11,881,336 of these words total

(b) How many of these words contain no repeated letters?

The first letter can be any of them, so L1 = 26.

At the second letter, the first one cannot be repeated, so L2 = L1 - 1 = 25.

At the third letter, nor the first nor the second one can be repeated, so L3 = L1 - 2 = 24

This logic applies until L5

So we have

26-25-24-23-22

In total there are

26*25*24*23*22 = 7,893,600

of these words with no repeated letters.

(c) How many of these words start with an a or end with a z or both (repeated letters are allowed)?

T = T_{1} + T_{2} + T_{3}

T_{1} is the number of words that start with an a and do not end with z. So we have

1 - 26 - 26 - 26 - 25

The first letter can only be a, and the last one cannot be z. So:

T_{1} = 26^{3}*25 = 439,400

T_{2} is the number of words that start with any letter other than a and end with z. So we have

25 - 26 - 26 - 25 - 1

The first letter can be any of them, other than a, and the last can only be z. So:

T_{2} = 26^{3}*25 = 439,400

T_{3} is the number of words that both start with a and end with z. So:

1 - 26 - 26 - 26 - 1

The first letter can only be a, and the last can only be z. The other three letters could be anything. So:

T_{3} = 26^{3} = 17,576

T = T_{1} + T_{2} + T_{3} = 2*439,400 + 17,576 = 896,376

896,376 of these words start with an a or end with a z or both

4 0
3 years ago
Which number is an irrational number?
ad-work [718]
1. To solve this problem, you must keep on mind the followinwg information:

 You know that, by definition, an irrational number is a number that cannot be expressed as a fraction.

 2. Therefore, the correct answer is the option D. 

 3. To verify the answer you have:

 ∛16=2.51

 As you can see, the result is 2.51 and the decimal number 2.51 cannot be expressed as a fraction.
3 0
3 years ago
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