Okay, so total dogs are 49.
So we know if x=large dogs and y=small dogs, then x+y=49.
Next we are told that there are 36 MORE small dogs than large dogs. We can take that more meaning addition, and x being our value for large dogs. So y=x+36.
After that we now know what value we can plug in for y. So x+x+36=49.
We can then simplify it to 2x+36=49.
Subtracting the 36 from both sides, leaves you with 2x=13.
Followed by dividing both sides by 2, gives you x=6.5. Or 6.5 large dogs.
Now we can plug this into our formula for the small dogs (y=x+36) to give us y=6.5+36, which simplifies to y=42.5. Or 42.5 small dogs. Which is our answer.
We can double check it by adding the small and large dogs together, 6.5+42.5, which gives us 49, our total entries.
Answer:
6.23% probability that the fourth part retrieved from stock is the first defective
Step-by-step explanation:
For each part, we have that:
8% probability of being defective.
100-8 = 92% probability of not being defective.
The parts are independent of each other.
What is the probability that the fourth part retrieved from stock is the first defective?
The first three work correctly, each one with a 92% probability.
The fourth is defective, with an 8% probability.
P = 0.92*0.92*0.92*0.08 = 0.0623
6.23% probability that the fourth part retrieved from stock is the first defective
• 56 = 16
so 16 pizzas are pepperoni
19 pizzas are cheese
And the rest is Veggie
So now add 16 and 19 which is 35
Now subtract that from 50 which is 15
So 15 pizzas were Veggie pizzas
Try this solution:
1. m∠A=m∠L; m∠B=m∠M and m∠C=m∠N;
2. m∠B=m∠M=35° and m∠C=m∠N=95°;
3. m∠A=m∠L=180°-(m∠B+m∠C)=180-35-95=50°
answer: 50°
Answer:
54
Step-by-step explanation:
since n = 3
= -2n ( 5n+n-8-3n)
= -2 (3) ( 5+(3)-8-3(3) )
= -6 (5+3-8-9)
= -6 (5-5-9)
= -6 (-9)
= 54.