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Diano4ka-milaya [45]
3 years ago
13

50 + x^2/20 + x/20=5x

Mathematics
1 answer:
Vanyuwa [196]3 years ago
5 0
Answer:  x = 87.582 , 11.148 .
_______________________________________
Explanation
_________________________________
Given:
_________________________________
   50 + (x²/20) + (x/20) = 5x ;  Solve for "x" ;
_________________________________
  → First, let us multiply the entire equation (both sides) by "20" ; to get rid of the fractions ;
____________________________________
  20 * {50 + (x²/20) + (x/20) = 5x } ;
____________________________________
 to get: 
____________________________________
1000 + x² + x = 100x ; 
____________________________________
Subtract "x" from each side ;
____________________________________
1000 + x² + x − x  = 100x  <span>− x ; 

to get:  1000 + x</span>² = 99x ; 

Rewrite as:

x² + 1000 = 99x ;

Subtract "99x" from each side of the equation:
______________________________________
   x² + 1000 − 99x = 99x − 99x ;

to get: 

   x² − 99x + 1000 = 0 

This expression is written is "quadratic format" ; that is:
_______________________________________________
   " ax² + bx + c  = 0 ;  a ≠ 0 " ;  
 
                in which:  a = 1 (implied coefficient of "1"; since anything                                                    multiplied by "1";  is that same value) ;

                               b = -99 ;
                                
                               c = 1000 ;
____________________________________________________
       →  So, we can solve for "x" using the quadratic equation formula (since the expression cannot be factored):
_________________________________________________
   x =   {- b ± √(b² <span>− 4ac) } / {2a} ;
_____________________________________________________
</span>Note:  - b =  - (-99) = 99 ;
__________________________________ 
            b² = (-99)² = 9801 .
__________________________________
         4ac = 4*a*c = 4*1*1000 = 4000 ;
__________________________________
             (b² − 4ac)  = 9801 − 4000 = 5801
____________________________________________
           √ (b² − 4ac) =  √(5801) = 76.16429609731846
____________________________________________
            2a = 2*a = 2*1 = 2 
____________________________________________
Rewrite the quadratic formula:
____________________________________________
    x  =  { - b ± √(b² − 4ac) } / {2a}  ;
____________________________________________

    → x = (99 ± 76.16429609731846) / 2 ; 
_____________________________________________
And, with the "±" ; we have 2 (TWO) potential solutions:
_______________________________________________
Case 1)
_______________________________________________
    →   x = (99  + 76.16429609731846) / 2 ;

             =  (175.16429609731846) / 2

             =  87.58214804865923 ;  →round to: 87.582 .
___________________________________________________
Case 2)
___________________________________________________
  →   x  =  (99 − 76.16429609731846) / 2 ;
 
            =   (22.83570390268154) / 2 ;
       
            =  11.41785195134077 ;  round to:  11.418.
______________________________________________
Answer:  x  =  87.582 , 11.148 .
_______________________________________________
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