Answer:
f[g(1)] = 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2x + 1
g(x) = 3x - 2
<u>Step 2: Find g(1)</u>
- Substitute in <em>x</em>: g(1) = 3(1) - 2
- Multiply: g(1) = 3 - 2
- Subtract: g(1) = 1
<u>Step 3: Find f[g(1)]</u>
- Substitute in g(1): f[g(1)] = 2(1) + 1
- Multiply: f[g(1)] = 2 + 1
- Add: f[g(1)] = 3
Given:
Consider the height of the rocket, in feet after x seconds of launch is

To find:
The time at which the rocket will reach its max, to the nearest 100th of a second.
Solution:
We have,

It is a quadratic polynomial with negative leading coefficient. So, it is a downward parabola.
Vertex of a downward parabola is the point of maxima.
To find the time at which the rocket will reach its max, we need to find the x-coordinate of the vertex.
If a quadratic function is
, then the vertex is

Here,
.
So,



So, x-coordinate of the vertex is 4.75.
Therefore, the rocket will reach its max at 4.75 second.
Step-by-step explanation:
7x - 3x=5 + 7
we will plus --
10x =12
x=12÷10 or 10 /12
x=12.2
Answer:
radius = 6.15
Step-by-step explanation:
cuz ik can u mark me brainliest?
Answer:
B, 3 and 5
Step-by-step explanation: