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Nutka1998 [239]
2 years ago
5

The box plots represent the ages of pennies in two 50-cent rolls. By looking at the plots, Beth says that the two means are abou

t 5 years apart. Which is true about Beth’s statement?

Mathematics
2 answers:
Neporo4naja [7]2 years ago
6 0

Answer:

D)She may not be correct because means cannot be determined from Box plots.

Step-by-step explanation:

Box plot -Boxplot is a way to show the spread and centers of a data setboxplot and also called a box and whisker plot,

Box plot tells us about :

1) Mininmum value

2) 25th Percentile value

3)Median

4) 75th Percentile value

5)Maximum value

6) Interquartile Range

Now we are given that By looking at the plots, Beth says that the two means are about 5 years apart.

So,Option D is true

She may not be correct because means cannot be determined from Box plots.

alexdok [17]2 years ago
5 0

Answer:

She may not be correct because means cannot be determined from the box plots

Step-by-step explanation:

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The building is 36 feet tall.

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Nayo draws a quadrilateral. it has adjacent sides measuring 16 inches and 20 inches and a diagonal measuring 25 inches. is her q
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I have a 79.43 and if I add 10% would it raise it to 80% grade wise
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87 grade

Step-by-step explanation:

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4 0
2 years ago
PLEASE HELP! 20 POINTS 1) A ball is thrown starting at a time of 0 and a height of 2 meters. The height of the ball follows the
drek231 [11]

Answer:

1) The height of the ball from 0 to 5  seconds are;

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2)  The correct option is;

D. -16·t² + 25·t + 1

Step-by-step explanation:

1) The equation of motion of the ball is given as follows;

H(t) = -4.9·t² + 25·t + 2

The height of the ball from 0 to 5 seconds are;

H(0) = -4.9×(0)² + 25×(0) + 2 = 2

H(1) = -4.9×(1)² + 25×(1) + 2 = 22.1

H(2) = -4.9×(2)² + 25×(2) + 2 = 32.4

H(3) = -4.9×(3)² + 25×(3) + 2 = 32.9

H(4) = -4.9×(4)² + 25×(4) + 2 = 23.6

H(5) = -4.9×(5)² + 25×(5) + 2 = 4.5

Therefore, we have;

The height of the ball are

At t = 0 second, height = 2

At t = 1 second, height h = 22.1

At t = 2 seconds, height h = 32.4

At t = 3 seconds, height h = 32.9

At t = 4 seconds, height h = 23.6

At t = 5 seconds, height h = 4.5

2) Given that the equation of the ball is that of a projectile motion, such as follows;

h = h₀ + v₀·sin(θ₀)·t - 1/2·g·t² which is equivalent to h = -1/2·g·t²+ h₀+v₀·sin(θ₀)·t

it is best represented by the quadratic equation of an upside down parabola which is option D. -16·t² + 25·t + 1

6 0
3 years ago
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