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Nutka1998 [239]
3 years ago
5

The box plots represent the ages of pennies in two 50-cent rolls. By looking at the plots, Beth says that the two means are abou

t 5 years apart. Which is true about Beth’s statement?

Mathematics
2 answers:
Neporo4naja [7]3 years ago
6 0

Answer:

D)She may not be correct because means cannot be determined from Box plots.

Step-by-step explanation:

Box plot -Boxplot is a way to show the spread and centers of a data setboxplot and also called a box and whisker plot,

Box plot tells us about :

1) Mininmum value

2) 25th Percentile value

3)Median

4) 75th Percentile value

5)Maximum value

6) Interquartile Range

Now we are given that By looking at the plots, Beth says that the two means are about 5 years apart.

So,Option D is true

She may not be correct because means cannot be determined from Box plots.

alexdok [17]3 years ago
5 0

Answer:

She may not be correct because means cannot be determined from the box plots

Step-by-step explanation:

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Sandy has four boxes filled with pink ribbons and yellow ribbons. The table shows the number of pink and yellow ribbons in each
Virty [35]
There would be 3 boxes of pink ribbon and 2 of yellow ones
7 0
4 years ago
Please help!!!!
meriva

answer 16.99%

We are given this function:

8700 is the initial amount.

1.04 shows the change of original amount. This is decimal form of percentage. We need to transform it into regular percentage.

1.04 * 100% = 104%

Now we observe this number. If it is greater than 100% we have growth, if it is lower than 100% it is decay, and if it is equal to 100% than there is no change.

In our case this number is greater than 100% so we have growth. To determine the percentage rate we must substract 100% as it represents the original amount.

104% - 100% = 4%

This would be our solution if we don't have an exponent.

We have exponent so first step is to calculate the number and then we repeat the steps from above.

1,16985856 * 100% ≈ 116,99%

116.99% - 100% = 16.99%

So, final solution is growth of 16.99%

bran-list please

7 0
3 years ago
There are 158 students registered for American History classes. There are twice as many students registered in second period as
Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<h3>x = 28</h3>

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<h3>y = 56</h3>

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

<h3>z = 74</h3>

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

5 0
3 years ago
49767269 x 327686000 - 1029 + 1101 / 32
mars1129 [50]

Answer:

16308037309533006\frac{13}{32}

Step-by-step explanation:

49767269 × 327686000 - 1029 + \frac{1101}{32}

= 16308037309534000 - 1029 + \frac{1101}{32}

= 16308037309532972 + 34\frac{13}{32}

= 16308037309533006\frac{13}{32}

8 0
3 years ago
What is 92 divided by 828
Natalija [7]
The answer is 9. if you wanna do it the long way buit a calculator is easier
3 0
3 years ago
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