Sandy has four boxes filled with pink ribbons and yellow ribbons. The table shows the number of pink and yellow ribbons in each
1 answer:
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Answer:
Option B) {(1, -1), (-3, -3), (2, 4)}
Step-by-step explanation:
<u><em>The correct inequality is </em></u>
The solution of the inequality is the shaded area above the dashed line
see the attached figure to better understand the problem
we know that
If a ordered pair satisfy the inequality, then the ordered pair must lie in the shaded area of the solution
<u><em>Verify each case</em></u>
case A) {(6, 1), (-1, -3), (4, 4)}
ordered pair (6,1)
For x=6, y=1
substitute in the inequality
---> is not true
therefore
The point not satisfy the inequality
case B) {(1, -1), (-3, -3), (2, 4)}
ordered pair (1,-1)
For x=1, y=-1
substitute in the inequality
---> is true
so
The point satisfy the inequality
ordered pair (-3,3)
For x=-3, y=3
substitute in the inequality
---> is true
so
The point satisfy the inequality
ordered pair (2,4)
For x=2, y=4
substitute in the inequality
---> is true
so
The point satisfy the inequality
therefore
The set contains only points that satisfy the inequality
case C) {(1, -1), (-3, -3), (4, -2)}
ordered pair (4,-2)
For x=4, y=-2
substitute in the inequality
---> is not true
therefore
The point not satisfy the inequality
case D) {(-1, -3), (-3, -3), (2, 4)}
ordered pair (-1,-3)
For x=-1, y=-3
substitute in the inequality
---> is not true
therefore
The point not satisfy the inequality
Answer:
a.P<x<9.85 orx>10.15)=0.3174, Total defects=317.4
b.p=0.0026,total defects=2.6
c.Less of the items produced will be classified as defects.
Step-by-step explanation:
a.The standard score,z, is esentially x reduced by process mean then divided my process standard deviation.
Total defects=Production*Probability
=0.3174*1000
b.
therefore:-
Defects=Probability*Production
=0.0026*1000
=2.6
c.Reducing process variation results in a significant reduction in the number of unit defects.