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Wewaii [24]
3 years ago
11

FOR BRAINLIEST ANSWER, SOLVE APPLICATION USING ALGEBRA. TYPE THE EQUATION OR INEQUALITY AND PLEASE SHOW WORK. a) If the sales ta

x on a purchase came to $48, what was the original price (before tax) and what is the final price (after tax)? (Use 6% for the sales tax rate).
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
7 0
The sales tax is 2.88 because 6% of 48 is 2.88 so the original price before tax was applied was 45.12
barxatty [35]3 years ago
3 0

Step-by-step explanation:

before tax it would be 6/100×48=$2.88

so therefore before tax = $48-2.88=$45.12

final price after tax =$48+2.88=$50.88

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3 years ago
A gas station operates two pumps, each of which can pump up to 10,000 gallons of gas in a month. the total of gas pumped at the
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Given that a<span> gas station operates two pumps, each of which can pump up to 10,000 gallons of gas in a month and that the total of gas pumped at the station in a month is a random variable y (measured in 10,000 gallons) with a probability density function (p.d.f.) given by

f(y)=\begin{cases}&#10;      cy, & \text{if} \ \ 0\ \textless \ y\ \textless \ 1 \\&#10;      (2-y), & \text{if} \ \ 1\leq y\ \textless \ 2 \\&#10;      0, & \text{elsewhere}&#10;    \end{cases}

Part A:

The value of c that makes f(y) a pdf is obtained as follows:

F(\infty)= \int\limits^{\infty}_{-\infty} {f(y)} \, dy=1  \\  \\ \Rightarrow \int\limits^1_0 {cy} \, dy +\int\limits^2_1 {(2-y)} \, dy=1 \\  \\ \Rightarrow \left. \frac{cy^2}{2} \right]^1_0+\left[2y- \frac{y^2}{2} \right]^2_1=1 \\  \\ \Rightarrow  \frac{c}{2} +4-2-2+ \frac{1}{2} =1 \\  \\ \Rightarrow \frac{c}{2} = \frac{1}{2}  \\  \\ \Rightarrow \bold{c=1}



Part B:

We compute E(y) as follows:

E(y)=\int\limits^{\infty}_{-\infty} {yf(y)} \, dy \\  \\ =\int\limits^1_0 {y^2} \, dy +\int\limits^2_1 {(2y-y^2)} \, dy \\  \\ =\left. \frac{y^3}{3} \right]^1_0+\left[y^2- \frac{y^3}{3} \right]^2_1 \\  \\ = \frac{1}{3} +4- \frac{8}{3} -1+ \frac{1}{3}  \\  \\ =1

Therefore, E(y) = 1.
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3 years ago
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