Question

In a shipment of 71 vials, only 13 do not have hairline cracks. If you randomly select 2 vials from the shipment, what is the probability that none of the 2 vials have hairline cracks.

Answer 1

Answer:

0.0313

Step-by-step explanation:

Given that in the shipment of 71 vials, only 13 do not have hairline cracks

Probability of not having a hairline cracks = $\frac{13}{71}$

If you randomly select 2 vials from the shipment

(Probability of not having a hairline cracks)' = $\frac{13-1}{71-1}$ = $\frac{12}{70}$

what is the probability that none of the 2 vials have hairline cracks.

i.e $(\frac{13}{71}) * (\frac{12}{70})$

= 0.183 × 0.171

= 0.0313

Hence, the probability that none of the 2 vials have hairline cracks = 0.0313