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Andrei [34K]
3 years ago
7

In a shipment of 71 vials, only 13 do not have hairline cracks. If you randomly select 2 vials from the shipment, what is the pr

obability that none of the 2 vials have hairline cracks.
Mathematics
1 answer:
yanalaym [24]3 years ago
6 0

Answer:

0.0313

Step-by-step explanation:

Given that in the shipment of 71 vials, only 13 do not have hairline cracks

Probability of not having a hairline cracks = \frac{13}{71}

If you randomly select 2 vials from the shipment

(Probability of not having a hairline cracks)' = \frac{13-1}{71-1} = \frac{12}{70}

what is the probability that none of the 2 vials have hairline cracks.

i.e (\frac{13}{71}) * (\frac{12}{70})

= 0.183 × 0.171

= 0.0313

Hence, the probability that none of the 2 vials have hairline cracks = 0.0313

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2. 2(x+1.25) = 3.5
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John buys 3 pounds of cherries and 2 pounds of bananas he pays a total of $24.95 the bananas cost $6.50 less per pound than the
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John will pay $8.68 for the combined cost of 1 pound of banana and 1 pound of cherries.

Let: b=cost of banana per pound and c=cost of cherries per pound

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3c + 2b =$24.95

Equation 2: The cost of bananas is $6.50 less than a pound of cherries.

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We can substitute the second equation into the first one to solve for the cost of cherries per pound.

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The combined cost of 1 pound of banana and 1 pound of cherries is $1.09 + $7.59 or $8.68.

For more information regarding the system of equations, please refer to brainly.com/question/25976025.

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